Assuming that the density of the solution in 1 gdm-3 :
1 litre = 1dm3= 1 kg = 1000g
290 grams
The average concentration of salt in seawater is around 35 grams per liter. This means there are approximately 35 grams of salt in a liter of seawater.
Tears contain about 3.2 grams of salt or sodium per liter. PS: That would mean, NO chloride is available.
35
it equals exactly 2000 things that equals another thing which also equals another thing. there hope this helped bye :P
35
To prepare a 3% solution of sulfosalicylic acid, you would need 30 grams of sulfosalicylic acid for every 1 liter of solution.
To make a 10% NaOH solution, you would need 100 grams of NaOH per liter of water. So to make 1 liter, you would need 100 grams of NaOH.
The density of urea is approximately 1.32 grams per milliliter. Therefore, in 1 liter of urea solution, there would be roughly 1320 grams of urea.
To prepare a 0.01N solution of sodium metabisulfite, you would need 2.31 grams of sodium metabisulfite per liter of solution.
To find the concentration of a solution in grams per liter, you need to divide the mass of the solute (in this case, 80 grams of NaCl) by the volume of the solution (2 liters). Therefore, the concentration of the solution would be 80 grams divided by 2 liters, which equals 40 grams per liter.
1% solution = 1 gram per 100 mL, 10 grams per liter 20 grams
One degree Brix (°Bx) is equivalent to 1 gram of sucrose in 100 grams of solution.
1 liter = 1000 mL 1 gram = 1000 mg So there are 45,000 mg in 1 liter divided by 1000 mg per gram = 45 grams/liter
Depends on the material in question.
290 grams
To prepare a 10 grams per liter solution of hydrochloric acid (HCl), you would weigh out 10 grams of HCl and dissolve it in enough water to make 1 liter of solution. Make sure to wear appropriate protective gear and work in a well-ventilated area when handling HCl as it is a corrosive chemical.