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To prepare a 3% solution of sulfosalicylic acid, you would need 30 grams of sulfosalicylic acid for every 1 liter of solution.
To make a 10% NaOH solution, you would need 100 grams of NaOH per liter of water. So to make 1 liter, you would need 100 grams of NaOH.
The density of urea is approximately 1.32 grams per milliliter. Therefore, in 1 liter of urea solution, there would be roughly 1320 grams of urea.
To prepare a 0.01N solution of sodium metabisulfite, you would need 2.31 grams of sodium metabisulfite per liter of solution.
1% solution = 1 gram per 100 mL, 10 grams per liter 20 grams
Assuming that the density of the solution in 1 gdm-3 : 1 litre = 1dm3= 1 kg = 1000g
One degree Brix (°Bx) is equivalent to 1 gram of sucrose in 100 grams of solution.
1 liter = 1000 mL 1 gram = 1000 mg So there are 45,000 mg in 1 liter divided by 1000 mg per gram = 45 grams/liter
Depends on the material in question.
290 grams
Approximately 770 grams of ammonium sulfate can dissolve in one liter of water to form a saturated solution at room temperature.
129 (grams per liter) = 129,000,000 micrograms per liter.