To find the concentration of a solution in grams per liter, you need to divide the mass of the solute (in this case, 80 grams of NaCl) by the volume of the solution (2 liters). Therefore, the concentration of the solution would be 80 grams divided by 2 liters, which equals 40 grams per liter.
The concentration of the solution is calculated by dividing the mass of the solute by the volume of the solution. In this case, the concentration of the iron II chloride solution is 200 grams divided by 450 mL, which is approximately 0.44 grams/mL.
The concentration of the solution can be calculated by dividing the mass of the solute (12 grams) by the volume of the solution (3.3 mL) and converting to the appropriate units. This will give you the concentration of ammonium sulfite in grams per milliliter.
You would have a saturated solution because at that temperature and concentration, the amount of sodium chloride being dissolved is in equilibrium with the amount that can be dissolved. Any more added would exceed its solubility.
The component water is the solvent in this case.
To make a 7.5% solution of sodium carbonate in water, add 7.5 grams of sodium carbonate to 100 mL of water and stir until the sodium carbonate is completely dissolved. This will give you a 7.5% (w/v) solution of sodium carbonate.
You can determine the concentration of the solution. First calculate the concentration by dividing the mass of the solute by the volume of the solution (55g/100mL). This would give you the concentration in g/mL, which can be converted to g/L by multiplying by 10. This would give you the concentration of the solution in grams per liter.
The percentage concentration of a solution can be calculated by dividing the mass of the solute by the total mass of the solution and then multiplying by 100. In this case, if 60 grams of sulfuric acid are dissolved in 1 liter of solution, the concentration would be (60g/1000g) x 100 = 6%.
To determine the number of grams of pure sodium hydroxide present in a solution with a known volume, you need to know the concentration of the solution in g/ml. Then you can use the formula: grams = concentration (g/ml) x volume (ml)
The concentration of a saturated solution of copper sulfate is approximately 25% by weight, which means that 25 grams of copper sulfate are dissolved in 100 grams of water at a specific temperature. At room temperature, this solution is around 47-50 grams of copper sulfate per 100 milliliters of water.
In chemistry, the concentration of a substance in solution is determined by molarity, which is symbolized by "M". This indicates the number of moles of a substance dissolved in one liter of a solvent (usually water). For example: - 1 mole of sodium chloride = 58 grams - If 116 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 2-molar (2 M) solution of sodium chloride. - If 232 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 4-molar (4 M) solution of sodium chloride.
After 50 grams of water evaporate, you will be left with 50 grams of water in which the 3.0 grams of salt is dissolved. So, your solution will now contain 3.0 grams of salt dissolved in 50 grams of water.
The concentration of NaCl in a solution that contains 0.9 NaCl is 0.9 grams of NaCl per 100 grams of solution.
The concentration of a solution can be expressed in many ways. One of them is as the molarity of the solution. A solution with molarity equal to one has one mole of the solute dissolved in every liter of the solutions
The concentration is 550 g/L (55 x 10).
To determine the grams of PbF2 that will dissolve, first calculate the concentration of Pb2+ ions that will be in equilibrium with NaF. Use the Ksp expression to find the solubility of PbF2 in terms of Pb2+ concentration. Then convert this concentration to grams of PbF2 dissolved in the solution.
The concentration of the solution is calculated by dividing the mass of the solute by the volume of the solution. In this case, the concentration of the iron II chloride solution is 200 grams divided by 450 mL, which is approximately 0.44 grams/mL.
An aqueous solution has 0.0070 gram of oxygen dissolved in 1000. grams of water. calculate the dissolved oxygen concentration of this solution in parts per million?A. 17ppm B. 27ppm C. 7ppm D. 7ppm