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Concentrated hydrochloric acid is 37.0 percent by mass HCl and has a specific gravity of 1.19 What volume of this acid must be diluted to one liter to produce 0.300 M solution of the acid?
Wiki User
∙ 13y ago
Molarity =(% by weight x density x 1000 mL/litre)/(Molecular weight x 100%)
%by weight ={(Molarity x Molecular Weight)/(density x 1000 mL/litre)} x 100%
Molecular weight - grams/mol (36.461 g/mol for HCl)
Molarity - mol/litre
Density - g/millilitre (Density may be listed as specific gravity)
For the given conditions Conc.HCl 37.0%, sp.gr. 1.19
Molarity = (37.0 x 1.19 x 1000)/(36.461 x 100)
Molarity = 12.07592 M
Available = 12.07592 M HCl
Required = 0.300 M HCl:
V1 x C1 = V2 x C2
(1000[mL] x 0.300[M]) / (12.07592[M]) = 24.84283[mL]
Dilute 24.84mL of 37.0% HCl to one liter to get 0.300M HCl solution.
Wiki User
∙ 13y ago
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