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What is the molarity of a solution prepared when 75.0 ml of a 4.00 m kcl solution is diluted to a volume of 0.500 l?
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∙ 14y ago
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∙ 14y ago
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What is the molarity of a solution where 4.00 moles of Potassium Chloride is dissolved in 3.00 L of solution?
The molarity of a solution given by the number of moles divided by the volume it contains. Hence, the molarity of KCl is 4.00/3.00 = 1.33 mol/L.
An alcoholic iodine solution is prepared by dissolving 4.65 g of iodine crystals in enough alcohol to make a volume of 235 mL Calculate the molarity of iodine in the solution?
molarity = no. of moles of solute/liter of solution no. of moles of I2 = mass in grams/molar mass = 4.65/253.81 = 0.01832 mol M = 0.01832 mol/0.235 L = 0.0780 mol/L
How do you calculate the molarity of the solution composed of 2.60 grams of NaCl in a total volume of 35 mL of solution?
Molarity means the number of mol of a substance per 1 litre of substance. Or figure out the number of mol of NaCl ((2.60/(23+35)=0.04) then multiply the 35ml by 28.571428 to get that to litres.. then multiply the number of mol by 28.571428 to get that to the number of mol. Therefore the answer is 1.142857M. See the Related Questions link "How do you prepare a solution of a specific concentration?"
A solution is made by dissolving 17.52g of nacl exactly 2000 ml what is the molarity of this solution?
concentration or molarity = number of moles/volume number of moles (n) = mass in grams of nacl/relative atomic mass of nacl n=17.52/(23+35.5) n = 0.2994872 mol volume = 2000/1000 = 2dm^3 molarity = 0.2994872/2 =0.15mol/dm^3
What is the molarity of sodium sulphate in a solution prepared by dissolving 15.5g in enough water to make 35ml of solution?
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
If 20.00mL of a 1.50M solution of KBr is diluted to a final volume of 150.0mL what is the new molar concentration?
initial molarity*initial volume= final molarity*final volume Initial molarity= 1.50M Initial volume= 20.00ml Final Volume=150.0ml Thus final molarity =1.50M*20ml/150ml=0.200M. New molar concentration= final molarity
What is the effect on the molarity of a solution of adding more solvent to a solution?
Adding more solvent to a solution decreases the molarity of the solution. This is based on the principle that initial volume times initial molarity must be equivalent to final volume times final molarity.
How do you calculated the value for molarity?
Molarity= No. of moles of solute/Volume of solution(in litre) or No. of moles of solute*1000/Volume of solution(in ml)
Definition of molarity and its equation?
molarity is the number of moles dissolved per volume of a solution in dm cube molarity=mass of solute in gram __________________ 1 * _________________ molecular mass of solute volume of solution in dm cube OR molarity=no.of moles ________________ volume of solution in dm cube
How do you calculate molarity of substance?
Molarity (M) = mole of solute (mol)/volume of solution that it is dissolved into (L) Make sure that the volume is converted to L if it isn't already, otherwise you will get wrong answers.
Why molality is not temperature dependent?
Molarity is the no of moles of solute per dm3 solution, the temperature change changes the volume so molarity becomes effected.
What concentration of ch3co2h will you have if 2L of a 5M solution diluted to a volume of 7.5L?
Use c1*V1=c2*V2 to calculate:(this goes for ANY molarity, not only for acetic acid as questioned)5(M) * 2(L) = x(M) * 7.5(L) , so x = molarity of the diluted = 1.3 M
What is the molarity of a solution prepared by dissolving 1.56 grams of gaseous HCl in enough water to make 26.8 mL of solution?
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
A solution of NaOH contains 20g of this compound in 2dm3 of this solution . What is molarity of this solution?
This sodium hydroxide solution has a molarity of 0,25.
What is the molarity of a solution containing 15.0g of aspartame dissolved in water and the solution volume is brought to 250.00mL by adding water?
The molarity is o,2.
Could you calculate the molarity of a solution you need to know the moles of solute and the?
volume of the solution
A student carefully diluted 25.0 ml 0.6 M NaOH solution in 475 ml of distilled water What is the molarity of the diluted solution of base?
Assuming that the 25.0 ml are added to the 475 ml of water, not diluted to that volume:Moles of NaOH in the original 25 ml = 25/1000 x 0.6 = 0.015 moles Final volume = 25 + 475 ml = 500 ml. We have 0.015 moles in 500 ml, so 0.03 moles in a litre, Molarity = 0.03.
