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An alcoholic iodine solution is prepared by dissolving 4.65 g of iodine crystals in enough alcohol to make a volume of 235 mL Calculate the molarity of iodine in the solution?
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molarity = no. of moles of solute/liter of solution
no. of moles of I2 = mass in grams/molar mass = 4.65/253.81 = 0.01832 mol
M = 0.01832 mol/0.235 L = 0.0780 mol/L
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