This value is 0,0164 M.
Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3
8300ml
This question makes no sense because pressure is not measured in mL.
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300 mL is equal to approximately 10.1 fluid ounces.
Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3
dissolve 100g in 300ml water
12.5
300mL
8L + 300ML = 8300ML or 8.3L
300ml (milliliters or cc) is 10.14 fluid ounces.
The concentration of the diluted solution will be 15(300/1000) = 4.5 %, if the percent is expressed on a weight/volume basis.
300mL is 30cL* There are 10mL per cL and 0.1cL per mL
If 3 litres has 10% solution of sugar, the sugar comprises 300ml (i.e. a tenth of 3000). If we want 300ml to be 5% then we need a total of 100/5 * 300 = 6,000ml (6 litres). So we need to add 3 more litres of water. In other words, to halve the percentage of sugar we need to double the total solution from 3 litres to 6 litres.
it is 60ml
1.25l, 150cl, 45cl, 750ml, 300ml, 0.35l
25%% rate:= 75/300 * 100%= 0.25 * 100%= 25%