2NH4NO3->2N2+O2+4H2O
2nh4no3 ---> 2n2 + o2 + 4h2o
N2 + 3F2 ==> 2NF32N, 6F on each side of the equation. It can help to create a table system for more complex equations.
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
-5
The hybridization of N i n N2 is sp.
y = kn / (1 + n2)First, let's express it with negative exponents:y = kn * (1 + n2)-1Then apply the chain rule:dy|dn = k(1 + n2)-1 - kn(1 + n2)-2 * 2nAnd simplify:dy|dn = k / (1 + n2) - 2n / kn(1 + n2)
2nh4no3 ---> 2n2 + o2 + 4h2o
The reaction is:2 NH4NO3 = 2 N2 + O2 + 4 H2O
(nh4)2co3 = co2 + h2o + 2 nh3
First, the decomposition of Ammonium Nitrate or NH4NO3 breaks down with heat into Nitrous Oxide (aka laughing gas) or simply N20 with the addition of H2O. So I'm not sure if trying to balance NH4NO3->H2O+N2+O2 makes sense. Instead I would suspect, NH4NO3 (s) → 2 H2O (g) + N2O (g) to be your answer.
Do you mean molecular formula? chemical equations or balanced chemical equations are only used in reactions. Ammonium is (N4H)+ whereas nitrate is (NO3)-, thus the molecular formula is NH4NO3
The balanced reaction for N2H4 + H2O2 --> N2 + H2O is N2H4 + 2H2O2 --> N2 + 4H2O
N2
co2 and h2o
H2O, CO2, N2, O2, C6H11O6 H2O, CO2, N2, O2, C6H11O6
N2 + o2 = no2
Four ammonia plus five oxygen molecules yields 4 nitrous oxide plus six water.
CO2 and H2O