Determine the empirical formula for the following a compound made from 26.19 nitrogen by mass 7.55 hydrogen by mass and 66.26 chlorine by mass with a total molar mass of 53.50 g?

Answer 1

Firstly divide percentages by molar mass of that element

N

26.19/14.01=1.87

H

7.55/1.01=7.48

Cl

66.26/35.45=1.87

Then divide the result of the first step by the smallest answer

N

1.87/1.87=1

H

7.48/1.87=4

Cl

1.87/1.87=1

Empirical Formula is NH4Cl

If the molar mass is 53.50 we can divide this by our empirical formulas molar mass to get the molecular formula.

so 53.50/(14.01+1.01x4+35.45)=53.50/53.5=1

so the molecular formula is NH4Cl