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44804.71629 mL of fluorine

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Q: Determine the volume of 76g of f2 at stp?
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Calculate the volume of F2 gas at stp produced by the electrolysis of 8.2g of KF?

The gram formula mass of KF = 39.098 + 18.999 = 58.097. Therefore, 8.2 g of KF contains 8.2/58.097 = 0.141 mole of fluorine atoms. Each mole of F2 requires two fluorine atoms, so that 0.070 moles of fluorine gas will result. An ideal gas at stp occupies 22.4 liters per mole, so that the volume of gas produced will be about 0.070 X 22.4 = 1.6 liters to the justified number of significant figures, unless fluorine gas at stp deviates too much from ideality.


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The easiest way to approach this is to remember molar volume: one mole of every (ideal) gas will occupy 22.4 liters at STP - a gas occupies 22.4 L/mol. Since we know that, we can set up a simple proportion that follows the thought process: if one mole of a gas occupies 22.4 liters (at STP), then 2.88 grams of methane occupies x liters. But before we do that, we have a problem: the measurement given is in the wrong units - it is in grams when molar volume is in moles. Therefore, we first need to convert 2.88 grams of methane to moles. To do this, we need the molar mass of the compound - the sum of all the atomic masses involved. Carbon = 12.0 grams Hydrogen = 1.01 grams × 4 atoms = 4.04 grams ------------------------------------------------------------- Methane = 16.04 grams To convert grams to moles: Grams of substance ÷ Molar mass (in grams) = Moles of substance 2.88 grams CH4 ÷ 16.04 grams CH4 = 0.180 moles CH4 Now we follow through with our proportion: 22.4 L/1 mol = x L/.180 mol x = 4.03 L 2.88 grams of methane occupies 4.03 liters at STP


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Is fluorine gas liquid or solid?

Fluorine can be in all 3 states of matter, however, at room temperature and normal pressure (STP) Fluorine is always in the gas form.It is a colourless (or pale yellow) gas existing as a diatomic molecules F2.


In which generation were recessive traits hidden in all the plants in Mendels experiments?

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