Want this question answered?
2 and -6
6.7m
how the force in each force pair related
The horizontal distance between them is from -5 to 1, that is 6 units. The vertical distance between them is from 1 to 6, that is 5 units. So, using Pythagoras, the distance between then, along the diagonal, is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) units.
Multiply the length of any side (they are all equal) by the perpendicular distance between a pair of parallel sides (either pair).
Use the distance formula. SQRT( (y1-y2)^2 + (x1-x2)^2) ) x1 and y1 are the first coordinate pair x2 and y2 are the second coordinate pair
crossing over
Two lines are said to be parallel if perpendicular distance between them is always constant. Length of a pair of parallel lines need not to be same. It can be different.
If one of a pair of charges is quadrupled and the distance between them doesn't change, then the electrostatic force between them is also quadrupled.
-- A road map with the distance marked between every pair of junctions. -- An azimuthal equidistant projection centered on either of those cities.
Grow a pair.
Distance = sqrt [(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt [(6 - 4)2 + (- 4 - 0)2]Distance = sqrt [(2)2 + (- 4)2]Distance = sqrt(4 + 16)Distance = sqrt(20)==============