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What is the maximum volume of 0.10 m naoh that can be completely neutralized by 0.20 ml of hcl?
To determine the maximum volume of 0.10 M NaOH that can be neutralized by 0.20 Ml of HCl, you need to use the equation: moles = Molarity × Volume. First, calculate the moles of HCl used (0.20 ml * 0.20 M) and then use the mole ratio from the balanced chemical equation to determine the moles of NaOH needed. Finally, divide the moles of NaOH by the concentration of NaOH to find the volume that can be neutralized.
What is the molArity of a hydrochloric acid solution 30.0mL of which is just neutralized by 48.0mL of 0.100M NaOH?
The reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is 1:1, so the moles of NaOH used in the reaction can be used to determine the moles of HCl in the solution. Using the volume and concentration of NaOH, you can calculate the moles of NaOH used. Then, using the balanced equation, you can determine the moles of HCl, which can be used to find the molarity of HCl in the solution.
What is the concentratuon of a hcl solution if 25.0 ml is required to neutralize 38.5 ml of a 0.500m solution of naoh?
To find the concentration of HCl, you can use the formula: moles of NaOH = moles of HCl. From the given information, you can calculate the moles of NaOH used to neutralize the acid. Then, use the volume and concentration of NaOH to determine the concentration of HCl.
What volume of NaOH was used in the titration?
To determine the volume of NaOH used in the titration, you need to know the concentration of the NaOH solution and the volume required to reach the endpoint. Use the formula: volume NaOH (L) = volume HCl (L) * concentration HCl / concentration NaOH.
A solution containing 3.76 g naoh in 361 ml water is titrated with 491 ml hcl what is the concentration of hcl in the original solution?
Given that the amount of NaOH is known, and the volume of HCl required for titration can be measured, you can calculate the concentration of HCl by using the balanced chemical equation and stoichiometry. The concentration of HCl in the original solution can be determined by dividing the moles of NaOH used in the reaction by the volume of HCl used. This calculation will yield the molarity of HCl in the original solution.
What is the maximum volume of 0.10 m naoh that can be completely neutralized by 0.20 ml of hcl?
To determine the maximum volume of 0.10 M NaOH that can be neutralized by 0.20 Ml of HCl, you need to use the equation: moles = Molarity × Volume. First, calculate the moles of HCl used (0.20 ml * 0.20 M) and then use the mole ratio from the balanced chemical equation to determine the moles of NaOH needed. Finally, divide the moles of NaOH by the concentration of NaOH to find the volume that can be neutralized.
What is the molArity of a hydrochloric acid solution 30.0mL of which is just neutralized by 48.0mL of 0.100M NaOH?
The reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is 1:1, so the moles of NaOH used in the reaction can be used to determine the moles of HCl in the solution. Using the volume and concentration of NaOH, you can calculate the moles of NaOH used. Then, using the balanced equation, you can determine the moles of HCl, which can be used to find the molarity of HCl in the solution.
What is the concentratuon of a hcl solution if 25.0 ml is required to neutralize 38.5 ml of a 0.500m solution of naoh?
To find the concentration of HCl, you can use the formula: moles of NaOH = moles of HCl. From the given information, you can calculate the moles of NaOH used to neutralize the acid. Then, use the volume and concentration of NaOH to determine the concentration of HCl.
What volume of NaOH was used in the titration?
To determine the volume of NaOH used in the titration, you need to know the concentration of the NaOH solution and the volume required to reach the endpoint. Use the formula: volume NaOH (L) = volume HCl (L) * concentration HCl / concentration NaOH.
A solution containing 3.76 g naoh in 361 ml water is titrated with 491 ml hcl what is the concentration of hcl in the original solution?
Given that the amount of NaOH is known, and the volume of HCl required for titration can be measured, you can calculate the concentration of HCl by using the balanced chemical equation and stoichiometry. The concentration of HCl in the original solution can be determined by dividing the moles of NaOH used in the reaction by the volume of HCl used. This calculation will yield the molarity of HCl in the original solution.
27.0 ml of 0.45 m naoh is neutralized by 20 ml of an hcl solution the molarity of the hcl solution is?
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
How do you standardization 1N hcl?
To standardize 1N HCl (hydrochloric acid), you would typically use a primary standard base, such as sodium hydroxide (NaOH), of known concentration to titrate the HCl solution. By carefully titrating the HCl with the NaOH, you can determine the exact concentration of the HCl solution. This information can then be used to adjust the concentration of the HCl solution as needed to make it accurately 1N.
If 25.00ml of 50m naoh is used to titrate 26.25ml of hcl to the equivalence point what is the concentration of the hcl?
First balance the equation of the reaction: NaOH + HCl ---> NaOH + H2O The ratio of moles is 1:1 M1V1 = M2V2 (molarity1 x volume1) = (molarity2 x volume2) M2 = M1V1 / V2 molarity2 = (molarity1 x volume1) / (volume2) M of HCl = 50M x 0.025 litres / 0.02625 litres = 47.6 M
How many mL of 1m NaOH would it take to neutralize 100 mL of an unknown HCL concentration?
You would need to know the concentration of the unknown HCl solution in order to determine the volume of 1M NaOH needed to neutralize it using the equation: M1V1 = M2V2. Without the concentration of HCl, it is not possible to calculate the volume of NaOH required for neutralization.
50 ml of hcl is titrated with a solution of 0.24 m naoh it requires 35 ml of naoh to reach the equivalence point what is the concentration of the hcl solution?
The moles of NaOH at the equivalence point are equal to the moles of HCl initially present. So, moles of NaOH = 0.24 mol/L * 0.035 L = 0.0084 moles. Since the moles of HCl are the same, and we have 50 ml = 0.05 L HCl, the concentration of HCl is 0.0084 moles / 0.05 L = 0.168 M.
What happenes when the active ingredients of acid and basis together?
A neutralization reaction. NaOH + HCl -> NaCl + H2O Neutralized and the products are a salt and water.
How do you calculate the concentration of hydrochloric acid from 23.74ml of 0.01470m NaoH for complete nutralisation of 25.00ml?
You can use the formula: (Molarity of NaOH) x (Volume of NaOH) = (Molarity of HCl) x (Volume of HCl). Plugging in the values, (0.01470 M) x (23.74 mL) = (Molarity of HCl) x (25.00 mL). Solve for the Molarity of HCl to find the concentration of hydrochloric acid.
