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Does HCl change in concentration when neutralized with NaOH?
Yes, when HCl is neutralized with NaOH, the concentration of HCl decreases as it reacts with NaOH to form water and NaCl. The concentration of the resulting NaCl solution will increase as the reaction progresses.
What volume of NaOH was used in the titration?
To determine the volume of NaOH used in the titration, you need to know the concentration of the NaOH solution and the volume required to reach the endpoint. Use the formula: volume NaOH (L) = volume HCl (L) * concentration HCl / concentration NaOH.
How do you prepare 0.5N NaOh?
Take half volume of 1.0 M NaOH and add another half volume of water. Or Take 20.0 gram NaOH , carefully dissolve this completely in ca. 0.9 L water and then fill up to 1.0 L end volume.
What is the molArity of a hydrochloric acid solution 30.0mL of which is just neutralized by 48.0mL of 0.100M NaOH?
The reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is 1:1, so the moles of NaOH used in the reaction can be used to determine the moles of HCl in the solution. Using the volume and concentration of NaOH, you can calculate the moles of NaOH used. Then, using the balanced equation, you can determine the moles of HCl, which can be used to find the molarity of HCl in the solution.
How many grams of solid NaOH are needed to prepare 500mL NaOH solution with a concentration of 0.4M?
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
Does HCl change in concentration when neutralized with NaOH?
Yes, when HCl is neutralized with NaOH, the concentration of HCl decreases as it reacts with NaOH to form water and NaCl. The concentration of the resulting NaCl solution will increase as the reaction progresses.
What volume of NaOH was used in the titration?
To determine the volume of NaOH used in the titration, you need to know the concentration of the NaOH solution and the volume required to reach the endpoint. Use the formula: volume NaOH (L) = volume HCl (L) * concentration HCl / concentration NaOH.
How do you prepare 0.5N NaOh?
Take half volume of 1.0 M NaOH and add another half volume of water. Or Take 20.0 gram NaOH , carefully dissolve this completely in ca. 0.9 L water and then fill up to 1.0 L end volume.
What is the molArity of a hydrochloric acid solution 30.0mL of which is just neutralized by 48.0mL of 0.100M NaOH?
The reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is 1:1, so the moles of NaOH used in the reaction can be used to determine the moles of HCl in the solution. Using the volume and concentration of NaOH, you can calculate the moles of NaOH used. Then, using the balanced equation, you can determine the moles of HCl, which can be used to find the molarity of HCl in the solution.
How do you dissolve phenol crystals?
Phenol is a strong acid so it may be neutralized by any base as NaOH
How many liters of naoh are in 1.3 moles of 3.42 m of naoh?
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
How many grams of solid NaOH are needed to prepare 500mL NaOH solution with a concentration of 0.4M?
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
How much of NaOH were used in the titration?
The amount of NaOH used in a titration depends on the volume and concentration of the NaOH solution used in the experiment. To calculate the exact amount of NaOH used, you would need to know the molarity of the NaOH solution and the volume used in the titration.
27.0 ml of 0.45 m naoh is neutralized by 20 ml of an hcl solution the molarity of the hcl solution is?
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
What is the pH of the solution formed by completely neutralizing 50 milliliters of 0.1 m hno3 with 50 milliliters of 0.1 m naoh at 298 k?
The reaction between HNO3 (acid) and NaOH (base) results in the formation of water and a salt, NaNO3. Since both the acid and base are of equal concentration and are completely neutralized, the resulting solution would be a neutral solution with a pH of 7.
What is the concentration of hydrochloric acid if 20.0 mL of acid is neutralized by 30.0mL of 0.20 N sodium hydroxide?
The moles of sodium hydroxide used can be calculated (moles = Molarity x Volume). Since it is a 1:1 reaction, the moles of hydrochloric acid neutralized will be the same. Using the moles and volume of hydrochloric acid, you can calculate its concentration (Molarity = moles / Volume).
How should one properly dispose of NaOH?
To properly dispose of NaOH, also known as sodium hydroxide or lye, it should be neutralized with an acid before disposal. This can be done by slowly adding a weak acid, such as vinegar, until the solution reaches a neutral pH level. Once neutralized, it can be safely poured down the drain with plenty of water. It is important to wear protective gear and handle NaOH with care to avoid skin irritation or burns.
