LED Light Bulbs are based on light-emitting diodes; the most notable advantages of LED light bulbs over conventional light bulbs are LED light bulbs last upwards of 50,000 hours. Additionally, LED light bulbs consume very little electricity. They are also shatterproof, run cool to the touch, and contain no Mercury or hazardous substances.
Even though it is connected to a 9 volt source, it is still a resistor.
Please do not try that, with new fresh batteries stream explosions sometimes result!!!!
no
The battery life (assuming it is a primary cell) is determined by the Ampere-hour drawn from it. You cannot connect a 3.5V bulb directly to a 9V battery. The bulb will fuse.
A car battery has six cells each producing two volts. A 9v alkaline battery has six cells each producing 1.5 volts. There are some obvious differences, like that a car battery can put out hundreds of amps and a 9v alkaline can only put out hundreds of milliamps, a 9v battery weighs 45 grams versus 45 pounds for a car battery, and so on.
They might burn but they would be very dim and the battery would last for a very short time. They are 12 volt lights therefore it will take 12 volts for them to burn at the level of brightness that they should.
you better not. you need a 9V regulator for this, not a resistor!
Black cables from Battery and buzzer to Lightswitch. Buzzer and Battery Red cables connected
No.
no
You can buy 9V batteries from almost any supermarket
In order to determine what size of resistor is required to operate an LED from a 9V battery, first start by knowing the current and voltage required for the LED. That information is available in the LED's specifications. For discussion purposes, lets assume a typical LED at 2.5V and 50mW. The translates to a forward current of 20mA. Build a simple series circuit containing a 9V battery, a resistor of an as yet unknown value, and the LED. By Kirchoff's current law, the current in the LED is the same as the current in the resistor, which is also the same as the current in the battery. This is 20ma. By Kirchoff's voltage law, the voltage across the LED plus the voltage across the resistor equals the voltage across the battery. This is 6.5V. (9 - 2.5) By Ohm's law, resistance is voltage divided by current, so the resistor is 6.5 / 0.02, or 325 Ohms. The nearest standard value to that is 330 Ohms. Cross check the power through the resistor. Power is voltage times current, or 6.5V times 0.02A, or 0.13W. A half watt resistor is more than adequate for this job.