Even though it is connected to a 9 volt source, it is still a resistor.
The formula you are looking for is I = E/R. Amps = Volts/Resistance. If you say it is normally a 2 Amp circuit, it normally draws 2 amps. Therefore the original resistance offered to the 12v battery is 2/12 = 6 Ohms. If you then connect a 12 Ohm resistor in series, they are added, so R = 18 Ohms. Now if you put 12v across this circuit it will draw 12/18 = 0.66 Amps. Or If you just put a 12 Ohm resistor across the 12v supply it will draw 1 Amp. If the circuit is protected by a 2 Amp fuse, it will not blow, but the resistor will get hot.
There is insufficient information in the question to properly answer it. You need to provide more information, such as the voltage across resistor four, or more details about the rest of the ciricuit. Please restate the question.
Current, by Ohm's Law, is voltage divided by resistance, so, 18 volts divided by 2 ohms is 9 amperes.
As you have not supplied any information, other than the resistance of the individual resistors, there is no way in which your question can be answered.
The total effective resistance of resistors in series is the sum of the individual resistances.Three 60-ohm resistors in series have a total effective resistance of (60 + 60 + 60) = 180 ohms.
The formula you are looking for is I = E/R. Amps = Volts/Resistance. If you say it is normally a 2 Amp circuit, it normally draws 2 amps. Therefore the original resistance offered to the 12v battery is 2/12 = 6 Ohms. If you then connect a 12 Ohm resistor in series, they are added, so R = 18 Ohms. Now if you put 12v across this circuit it will draw 12/18 = 0.66 Amps. Or If you just put a 12 Ohm resistor across the 12v supply it will draw 1 Amp. If the circuit is protected by a 2 Amp fuse, it will not blow, but the resistor will get hot.
1/2 watt (In theory you could use a "0.27 Watt" resistor, however there would be no safety factory and there is no standard value resistor that size.)
The answer is 6 ohms x 3 amps which is 18 v.
There is insufficient information in the question to properly answer it. You need to provide more information, such as the voltage across resistor four, or more details about the rest of the ciricuit. Please restate the question.
Current, by Ohm's Law, is voltage divided by resistance, so, 18 volts divided by 2 ohms is 9 amperes.
As you have not supplied any information, other than the resistance of the individual resistors, there is no way in which your question can be answered.
The answer is 1/(1/18+1/23.5)) 18, 1/x, +, 23.5, 1/x, =, 1/x gives the answer.
Depends on how you connect them together. Connected them in a series and you will have 18 volts. Connected them in parallel and you will still have 9 volts just double the capacity of 1 battery. Click the link to see these 2 connections.
They are equivalent.
I presume you mean wired to four ohms amplifier output: In this case, pair the two speakers in in series which will make the give you 18 Ohms and then join the two pairs in parallel which will result in approximately eight ohms. Then connect then in that format to the amplifier. It will work for you.
The total effective resistance of resistors in series is the sum of the individual resistances.Three 60-ohm resistors in series have a total effective resistance of (60 + 60 + 60) = 180 ohms.
California Connected - 2002 4-18 was released on: USA: 2005