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What is the total voltage for R1 20 ohms R2 30 ohms and R3 18 ohms?
Joshuahoward52
As you have not supplied any information, other than the resistance of the individual resistors, there is no way in which your question can be answered.
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∙ 10y ago
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Two resistors are connected in a parallel to a batterywhat is the voltage across these two resistors?
The resistors each have a value of 20 ohms. The way to discover it is to apply Ohm's law. It (Ohm's law) comes in 3 "flavors" that look a bit different but all say exactly the same thing. Here they are: E = I x R [Voltage equals current times resistance.] I = E/R [Current equals voltage divided by resistance.] R = E/I [Resistance equals voltage divided by current.] In these equations, voltage is E, current is I and resistance is R. They are measured in units of volts, amperes (or amps) and ohms, respectively. Your problem gives us an applied voltage of 8 volts and a current flow of 0.2 amps. The formula that probably works best is R = E/I for this one because you have volts and amps. In this case, R = 8/0.2 = 40 ohms. But that's the total resistance in the circuit, and you said that a pair of equal resistors are connected, so the pair of resistors has a total resistance of 40 ohms. The rule for finding total resistance for resistors in series is that we add them up. R1 + R2 = 40 ohms. And since R1 = R2 here, 2 x R1 or 2 = 40 ohms, and R1 or 2 = 20 ohms. Either resistor has a resistance of 20 ohms, and that means they both do. Easy as pie.
What resistance in ohms will allow 20 amperes of current to flow in an appliance if the voltage is 220 volts?
The formula you are looking for is R = E/I
There are three sources of resistance in a parallel circuit Two of them are rated at 20 ohms the other at 10 ohms What is the circuit's total resistance?
-- If the 20 ohms and the nother 10 ohms are configured in series, then the totalnet effective resistance is 30 ohms.-- If they are configured in parallel, then the total effective resistance is 62/3 ohms.
How much voltage does a resistor drop in a circuit with 20 volts 1kHz capacitor at 0.47 milli Farads and a 400 ohm resistor?
The reactance of the capacitor is 0.339 ohms, therefore the total impedance is sqrt(4002+0.3392) = 400.0001 ohms. So the resistor drops very nearly 20 volts, very slightly less.
A series LCR circuit consisting of R10 ohms and impedence 20 ohms is connected across an ac supply of 200 v rms The rms voltage across the capacitor is?
16.32 volts
What is the total resistance of 20 ohms?
Could it be.... 20 ohms(?)
What is the applied voltage of a circuit where current equals 40 amps and there are two resistances of 10 ohms each in series?
R total = R1 +R2 = 20 ohms. Voltage = Amps x Resistance = 40 x 20 = 800 volts. See related links below.
What is the total resistance of a series circuit with 5ohms10 ohms 20 ohms?
35 ohms
There are three souces of resistance in a parallel circuit Two of them are rated at 20 ohm the other at 10 ohms What is the circuit's total resistance?
Three resistors in parallel: 20 ohms, 20 ohms, 10 ohms.1/ total resistance = (1/10) + (1/20) + (1/20) = (2/20) + (1/20) + (1/20) = 4/20 = 1/5 mho.Total resistance = 5 ohms
How much current does a line with a voltage of 20 volts and a resistance of 40 Ohms?
The answer is 20 divided by 40, in amps.
Perallel circuit two of them are rated 20 ohms one is 10 ohms what is the cicuits total resistance?
5 ohms
Two resistors are connected in a parallel to a batterywhat is the voltage across these two resistors?
The resistors each have a value of 20 ohms. The way to discover it is to apply Ohm's law. It (Ohm's law) comes in 3 "flavors" that look a bit different but all say exactly the same thing. Here they are: E = I x R [Voltage equals current times resistance.] I = E/R [Current equals voltage divided by resistance.] R = E/I [Resistance equals voltage divided by current.] In these equations, voltage is E, current is I and resistance is R. They are measured in units of volts, amperes (or amps) and ohms, respectively. Your problem gives us an applied voltage of 8 volts and a current flow of 0.2 amps. The formula that probably works best is R = E/I for this one because you have volts and amps. In this case, R = 8/0.2 = 40 ohms. But that's the total resistance in the circuit, and you said that a pair of equal resistors are connected, so the pair of resistors has a total resistance of 40 ohms. The rule for finding total resistance for resistors in series is that we add them up. R1 + R2 = 40 ohms. And since R1 = R2 here, 2 x R1 or 2 = 40 ohms, and R1 or 2 = 20 ohms. Either resistor has a resistance of 20 ohms, and that means they both do. Easy as pie.
What resistance in ohms will allow 20 amperes of current to flow in an appliance if the voltage is 220 volts?
The formula you are looking for is R = E/I
There are three sources of resistance in a parallel circuit. two of them are rated at 20 ohms the other at 10 ohms. what is the circuits total resistance?
5 ohms
There are three sources of resistance in a parallel circuit two of them are rated at 20 ohms the other at 10 ohms what is the circuit's total resistances?
5 ohms.
There are three sources of resistance in a parallel circuit Two of them are rated at 20 ohms the other at 10 ohms What is the circuit's total resistance?
-- If the 20 ohms and the nother 10 ohms are configured in series, then the totalnet effective resistance is 30 ohms.-- If they are configured in parallel, then the total effective resistance is 62/3 ohms.
A series circuit contains an electric generator, three devices operated by electricity, and the necessary connecting wires. The resistances of the three devices are 20 ohms, 8 ohms, and 4 ohms. What is the total resistance in the circuit?
When a resistor is in series. Total resistance =R1+T2+R3. Therefore 20+8+4=32 The total resistance is 32 ohms.
