Yes, alpha decay occurs naturally, that is why radioactive material is dangerous, because we can't simply "turn off" the radioactive decay.
The decay equation for uranium-238 (U-238) decaying into an alpha particle (helium-4) can be represented as follows: (^{238}{92}\text{U} \rightarrow ^{4}{2}\text{He} + ^{234}_{90}\text{Th}). This equation shows the radioactive decay process of U-238 into an alpha particle and thorium-234.
No. Decay is the process, radiation is the product.
From weakest to strongest decay, the order is: Gamma decay - involves the emission of high-energy photons. Beta decay - involves the emission of beta particles (electrons or positrons). Alpha decay - involves the emission of alpha particles (helium nuclei).
Alpha decay is the type of radioactive decay in which positive particles, specifically alpha particles, are emitted. These alpha particles consist of two protons and two neutrons bound together, giving them a positive charge.
The type of decay for this process is alpha decay. In alpha decay, a heavy nucleus emits an alpha particle (helium-4 nucleus) to transform into a new element with a lower atomic number.
Alpha decay emits an alpha particle, which consists of two protons and two neutrons. Beta decay emits either an electron (beta minus decay) or a positron (beta plus decay).
I'm pretty sure its alpha.
In alpha decay, the emitted particle has a charge of 2.
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
The possible products of the alpha decay of uranium-238 are thorium-234 and helium-4. During alpha decay, the uranium nucleus releases an alpha particle (helium nucleus) and transforms into thorium-234.
Uranium-239 does NOT decay by alpha decay, it decays only by beta and gammadecay.
alpha decay