The equation for the alpha decay of 226Ra:
88226Ra --> 86222Rn + 24He
The alpha particle is represented as a helium (He) nucleus.
Radium-226--------------------Radon-222 + alpha
Radium-226 does not decay by beta decay. It decays by alpha decay to radon-222.
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
The equation for the alpha decay of radon-222 takes the following form. Radon-222 ----> He + Polonium. In an alpha decay, the atom loses 2 neutrons and 2 protons.
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
By alpha decay Th-230 is transformed in Ra-226.
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
Ra22688 = Rn22286 + (a)42+ (a)= an alpha particle, i can't do the symbol here
Radium-226 undergoes radioactive decay to become more stable. During this process, the nucleus emits an alpha particle, decreasing its atomic number and mass number. This transformation helps the nucleus achieve a more balanced and stable configuration.
undergo radioactive decay, releasing alpha particles. This decay process results in the transformation of the radium 226 nucleus into a different element, typically radon 222, along with the release of energy.
Radium 226 decays by alpha emission to Radon 222. A helium nucleus is emitted by alpha emission which makes the mass reduce by 4 and its atomic number by 2.
When thorium-230 decays by emitting an alpha particle, it transforms into radium-226. This decay process reduces the mass number by 4 and the atomic number by 2.