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When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
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What is the balanced nuclear equation for the alpha decay of thorium 230?
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
How do you write a balanced nuclear equation for the alpha decay of polonium -216?
Po-216- -----------------> Pb-212
How do you write a balanced nuclear equation for the formation of polonium-206 through alpha decay?
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
Write a balanced nuclear equation for the radioactive decay of a boron-10 plus a neutron results in the formation of another element and the release of an alpha particle?
Boron-10 (^10B) undergoing neutron capture forms boron-11 (^11B), followed by the emission of an alpha particle (helium-4 atom). The balanced nuclear equation would be: ^10B + n → ^11B + ^4He
Why does the presence of gamma rays not affect how a nuclear equation of alpha is balance?
Gamma rays do not have mass or charge, so they do not contribute to the balance of a nuclear equation that involves the emission of an alpha particle. The alpha particle carries away the mass and charge necessary to balance the nuclear equation.
What is the balanced equation for the alpha decay of radium 228?
224
220 RN yields to alpha particle po-216 what particle or type of radiation needs to be included to balance the equation?
To balance the nuclear equation, a beta particle (negatron) must be included. The balanced equation would be 220/88 Ra -> 4/2 He (alpha particle) + 212/86 Rn + 2 -1 e.
What is the nuclear equation for the decay of radium 226?
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
What is the balance nuclear equation for alpha decay of 251 N0?
The balance nuclear equation for the alpha decay of ^251No (Nobelium-251) is: [ ^{251}{102}No \rightarrow ^{247}{100}Fm + ^{4}_{2}\alpha ] In this equation, Nobelium-251 decays into Californium-247 while emitting an alpha particle ((^4_2\alpha)). The mass and atomic numbers are conserved in the reaction.
What is the nuclear decay equation for astatine 213?
The equation for the alpha decay of 213At: 85213At --> 83209Bi + 24He where the alpha particle is represented as a helium nucleus.
What is the nuclear decay equation for bohrium-265?
The equation for the alpha decay of 265Bh is:107265Bh --> 105261Db + 24He where the 24He is an alpha particle or helium nucleus.
What would the balanced equation for the alpha decay of thorium 229 be?
The balanced equation for the alpha decay of thorium-229, Th-229, is: Th-229 -> Ra-225 + He-4 This equation shows that a thorium-229 nucleus undergoes alpha decay to form a radium-225 nucleus and a helium-4 particle.
