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If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).

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14y ago
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13y ago

The equation for the alpha decay of 210Po is:84210Po --> 82206Pb + 24He

where He represents the alpha particle, which can also be viewed as a Helium nucleus.

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14y ago

210Po----------alpha particles emission----------206Pb

The half life of 210Po is 138,376 days.

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8y ago

The equation is:
Radon-210-----------------alpha particle---------------------Polonium-206

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Q: How do you write a balanced nuclear equation for the formation of polonium-206 through alpha decay?
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