How do you write a balanced nuclear equation for the formation of polonium-206 through alpha decay?

Answer 1

If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).

Answer 2

To write a balanced nuclear equation for the formation of polonium-206 through alpha decay, start with the parent nucleus, which is radium-210. Radium-210 undergoes alpha decay, emitting an alpha particle (helium nucleus) to form polonium-206 and an additional particle (usually a neutrino). The balanced nuclear equation for this process would be: (^{210}{88}Ra \rightarrow ^{206}{84}Po + ^4_{2}He).

Answer 3

The equation for the alpha decay of 210Po is:84210Po --> 82206Pb + 24He

where He represents the alpha particle, which can also be viewed as a Helium nucleus.

Answer 4

210Po----------alpha particles emission----------206Pb

The half life of 210Po is 138,376 days.

Answer 5

The equation is:
Radon-210-----------------alpha particle---------------------Polonium-206