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How do you write a balanced nuclear equation for the alpha decay of polonium -216?
Po-216- -----------------> Pb-212
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What is the balanced nuclear equation for the alpha decay of thorium 230?
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
What is the nuclear decay equation for Polonium?
210 4 214 84 PO -------> 2 alpha + 86 RN
What equation correctly represents alpha decay of polonium 214?
The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.
Which equation correctly represents the alpha decay of polonium 214?
The correct equation for the alpha decay of Polonium-214 is: 218/84Po -> 214/82Pb + 4/2He This shows the decay of Polonium-214 into Lead-214 and a Helium nucleus, where the atomic number and mass numbers are conserved.
What is the balanced reaction for the predominant method of decay of radon?
In the case of Rn-222, which is the "isotope of concern" because it occurs naturally, it decays as follows: 222Rn => 218Po + He+2 In this equation, we see the radon isotope Rn-222 emit an alpha particle (the helium nucleus) and undergo a transformation to become the polonium isotope, Po-218.
How do you write a balanced nuclear equation for the formation of polonium-206 through alpha decay?
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
What is the balanced nuclear equation for the alpha decay of thorium 230?
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
What is the nuclear decay equation for Polonium?
210 4 214 84 PO -------> 2 alpha + 86 RN
What equation correctly represents alpha decay of polonium 214?
The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.
Which equation correctly represents the alpha decay of polonium 214?
The correct equation for the alpha decay of Polonium-214 is: 218/84Po -> 214/82Pb + 4/2He This shows the decay of Polonium-214 into Lead-214 and a Helium nucleus, where the atomic number and mass numbers are conserved.
What is the balanced equation for alpha decay astatine-217?
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
Is polonium explosive?
Polonium itself is not explosive. It is a radioactive element that can spontaneously decay, emitting alpha particles. However, polonium can be used to trigger a fission reaction in a nuclear bomb as part of a beryllium-polonium initiator.
Write a balanced nuclear equation for the radioactive decay of a boron-10 plus a neutron results in the formation of another element and the release of an alpha particle?
Boron-10 (^10B) undergoing neutron capture forms boron-11 (^11B), followed by the emission of an alpha particle (helium-4 atom). The balanced nuclear equation would be: ^10B + n → ^11B + ^4He
Why does the presence of gamma rays not affect how a nuclear equation of alpha is balance?
Gamma rays do not have mass or charge, so they do not contribute to the balance of a nuclear equation that involves the emission of an alpha particle. The alpha particle carries away the mass and charge necessary to balance the nuclear equation.
What is the beta decay equation of radium-222?
The equation for the alpha decay of radon-222 takes the following form. Radon-222 ----> He + Polonium. In an alpha decay, the atom loses 2 neutrons and 2 protons.
What is the balanced equation for the alpha decay of radium 228?
224
What is the balanced reaction for the predominant method of decay of radon?
In the case of Rn-222, which is the "isotope of concern" because it occurs naturally, it decays as follows: 222Rn => 218Po + He+2 In this equation, we see the radon isotope Rn-222 emit an alpha particle (the helium nucleus) and undergo a transformation to become the polonium isotope, Po-218.
