210 4 214
84 PO -------> 2 alpha + 86 RN
Po-216- -----------------> Pb-212
The correct equation for the alpha decay of Polonium-214 is: 218/84Po -> 214/82Pb + 4/2He This shows the decay of Polonium-214 into Lead-214 and a Helium nucleus, where the atomic number and mass numbers are conserved.
The nuclear decay equation for Po-208 is: Po-208 → Pb-204 + He-4
The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.
N14
Po-216- -----------------> Pb-212
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
All nuclear decay is spontaneous.
The correct equation for the alpha decay of Polonium-214 is: 218/84Po -> 214/82Pb + 4/2He This shows the decay of Polonium-214 into Lead-214 and a Helium nucleus, where the atomic number and mass numbers are conserved.
The nuclear decay equation for Po-208 is: Po-208 → Pb-204 + He-4
Natural chromium is stable and does not decay/
Energy and electrical charge are two quantities that are always conserved in nuclear decay equation.
Polonium itself is not explosive. It is a radioactive element that can spontaneously decay, emitting alpha particles. However, polonium can be used to trigger a fission reaction in a nuclear bomb as part of a beryllium-polonium initiator.
The decay equation is:Co-60----------------------Ni-60 + e-
The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.
The equation for the beta decay of 17F: 917F --> 817O+ 10e + ve where the 10e is a positive beta particle or positron.
The equation for the beta decay of 14C: 614C --> 714N + -10e where the e is an electron.