What is the balanced equation for alpha decay astatine-217?

Answer 1

When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.

Answer 2

Polonium 210-----------alpha particles-----------Lead 206

Polonium 209-----------alpha particles-----------Lead 205

Polonium 208-----------alpha particles-----------Lead 204

For other isotopes see the list at: http://en.wikipedia.org/wiki/Polonium#Isotopes

Answer 3

First you must decide what isotope of platinum you are talking about. Most elements have several isotopes. Once you decide that, just subtract 2 protons from the number of protons, and 2 neutrons from the number of neutrons, to get the daughter product - since an alpha particle consists of 2 protons and 2 neutrons.

Answer 4

The balanced equation for alpha decay of Astatine-217 can be written as: [^{217}{85}At \rightarrow ^{213}{83}Bi + ^4_2He] In this process, astatine-217 decays into bismuth-213 and an alpha particle (helium-4).

Answer 5

The equation for the alpha decay of 213At is:85213At --> 83209Bi + 24He

representing the alpha particle as a helium nucleus.

Answer 6

Only one isotope of platinum can undergo alpha decay: platinum-190.

platinum-190 decays to osmium-186 which is stable

Answer 7

Here is an error: polonium 24 doesn't exist.

Answer 8

85At217 -----> 2He4 + 83Bi213