Radium 226 decays by alpha emission to Radon 222. A helium nucleus is emitted by alpha emission which makes the mass reduce by 4 and its atomic number by 2.
226 Ra 88 ---> 225 Ac 89 +W boson W boson ---> e- + neutron
This process is called alpha decay.
Radium-226 does not decay by beta decay. It decays by alpha decay to radon-222.
Oxygen-17 would become fluorine-17 after undergoing alpha decay, and then it would decay into oxygen-17 again after undergoing beta decay. Alpha decay involves emitting an alpha particle comprising two protons and two neutrons, while beta decay involves either emitting an electron (beta minus decay) or a positron (beta plus decay) to change the nucleus.
No, in alpha decay the atomic number of the daughter nucleus is decreased by 2 and the mass number is decreased by 4 compared to the isotope undergoing decay. This is because an alpha particle (helium nucleus) is emitted during alpha decay, resulting in a new daughter nucleus with a lower atomic and mass number.
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
226 Ra 88 ---> 225 Ac 89 +W boson W boson ---> e- + neutron
The decay of thorium by alpha decay the resultant nuclide is the element radium. The specific nuclide of radium cannot be determined unless we know which specific nuclide of thorium underwent alpha decay.
224
The naturally occurring isotope of radium we encounter is radium-226. It appears in the decay chain of uranium. When radium-226 undergoes alpha decay, radon-222 is the result. The equation looks like this: 88226Ra => 24He + 86222Rn The 24He is the alpha particle, which is a helium nucleus.
Radium-226--------------------Radon-222 + alpha
This process is called alpha decay.
Radium-226 does not decay by beta decay. It decays by alpha decay to radon-222.
By alpha decay Th-230 is transformed in Ra-226.
Nuclear decay.
The atomic number of an atom undergoing alpha decay decreases by 2. Not asked, but answered for completeness, the atomic mass number decreases by 4.
The equation for the alpha decay of radon-222 takes the following form. Radon-222 ----> He + Polonium. In an alpha decay, the atom loses 2 neutrons and 2 protons.