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Radium 226 decays by alpha emission to Radon 222. A helium nucleus is emitted by alpha emission which makes the mass reduce by 4 and its atomic number by 2.

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What is the nuclear equation for the decay of radium 226?

The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.


What is the beta decay of radium?

226 Ra 88 ---> 225 Ac 89 +W boson W boson ---> e- + neutron


When thorium decays by producing an alpha praticle the product nuclide is?

The decay of thorium by alpha decay the resultant nuclide is the element radium. The specific nuclide of radium cannot be determined unless we know which specific nuclide of thorium underwent alpha decay.


What is the balanced equation for the alpha decay of radium 228?

224


What is the new chemical identity of the radium atom after it has emitted an alpha particle?

The naturally occurring isotope of radium we encounter is radium-226. It appears in the decay chain of uranium. When radium-226 undergoes alpha decay, radon-222 is the result. The equation looks like this: 88226Ra => 24He + 86222Rn The 24He is the alpha particle, which is a helium nucleus.


What is the decay process does radium 226 undergo including the nuclear changes that occur?

Radium-226--------------------Radon-222 + alpha


What Type of Decay occurs when Thorium -229 decay to form radium -225?

This process is called alpha decay.


What is the beta decay of radium 226?

Radium-226 does not decay by beta decay. It decays by alpha decay to radon-222.


What element does thorium 230 decay into?

By alpha decay Th-230 is transformed in Ra-226.


What is the process that allows the nucleus of Radium to become stable?

Nuclear decay.


What happens to the atomic number of an atom undergoing alpha decay?

The atomic number of an atom undergoing alpha decay decreases by 2. Not asked, but answered for completeness, the atomic mass number decreases by 4.


What is the beta decay equation of radium-222?

The equation for the alpha decay of radon-222 takes the following form. Radon-222 ----> He + Polonium. In an alpha decay, the atom loses 2 neutrons and 2 protons.