The first card led to a trick establishes the suit for that trick. All players must follow suit if possible. A hand which has no cards in the led suit (and thus cannot follow suit) may play any card on the trick. If the card played is a trump, then the suit will be won by the trumping partnership, even if the ace is played. Thus, the ace of the led suit wins any trick which has not been trumped. The highest trump played to the trick wins a trumped trick. Note that when the contract is No Trump, the ace of the led suit always wins.
A Joker card does not have a standard rank among the other cards in a standard deck. It's value is usually assigned to it depending on which game you are playing. In cases of games where a Joker is declared to be a "Wild" card, the standand is usually that a "Natural" card beats a "Wild" card that has been declared to be a card of the same rank for that hand or play.
In most card games the ace is treated as the highest card in the suit. In a few, though, it's treated as the lowest, and in some games even though aces are higher than queens the suits of the two cards matter (one suit "trumps" the others, so a queen of hearts might beat an ace of clubs, if hearts are trumps).
yes the general order goes 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King, Ace except in some games such as 21 which ace can be either 1 or 14
No, three of a kind of anything beats any pair.
Joker beats ace
no
Two pair works like this, the higher pair determines who is the winner. Suppose I have two pair Aces and fives, that means I beat all two pair that have kings as the higher pair, and queens etc. So Aces and fives beats Kings and queens. Now, if there is tie then the second pair comes in, so Aces and fives loses to Aces and sevens.
The pair of queens beat the pair of tens, the nine and the ace are irrelevant. Queens are higher ranked than tens.
It depends on the type of poker game being played.In a game where aces are low (they are equivalent to the number 1). In that case yes, a pair of fives beats a pair of aces.In a game where aces are high, then no, the pair of aces definitely wins. A pair of aces is the highest single pair you can get in the game of poker, before getting two pair or higher.Both of these types of games are played in poker.
a pair of aces.
3 of a kind Aces can not beat a full house. In this particular case it is most likely that there was a pair and an ace already on the board, making the 3 aces and the pair on the board a higher full house then the other full house.
A pair of Aces & Deuces (Deuces = Two's) will win over a pair of Kings and Queens. A poker hand consist out of 5 cards. The highest card(s) win of course the hand. In this case I'm going to give you an example. Since there is no 5'th card I'll use X for it. A pair of Aces & Deuces will look like AA22X. In this case the highest pair (or valid combination of more then 2 cards) is the Aces. The pair of Kings & Queens looks like KKQQX. As you can see here, the highest pair (or valid combination of more then 2 cards) are the Kings. Because the Aces are of course higher then the Kings, the hand AA22X (or Aces and Deuces) win the hand.
i think its a pair but i have only recently started playing poker so im not sure
No, a full house beats two pair
No. Three of a kind beats two pair in poker hands.
no, it depends on what the other player(s) have(has)
Four queens would win at poker if nobody holds a better hand. For example, four queens would be beaten by four kings or four aces. But if nobody holds a better hand, four queens would be the winning hand.
The two pair, although lower, beat the pair of Aces.