3 of a kind Aces can not beat a full house.
In this particular case it is most likely that there was a pair and an ace already on the board, making the 3 aces and the pair on the board a higher full house then the other full house.
Three aces and two eights is a full house. Three Aces and two nines would win. As would three aces and two kickers 10 or higher.
No, a full house beats two pair
It depends on the type of poker game being played.In a game where aces are low (they are equivalent to the number 1). In that case yes, a pair of fives beats a pair of aces.In a game where aces are high, then no, the pair of aces definitely wins. A pair of aces is the highest single pair you can get in the game of poker, before getting two pair or higher.Both of these types of games are played in poker.
No.
Four of a kind in poker beats three of a kind. Even four deuces beats three aces.
No, a flush cannot beat a full house.
No. Three of a kind beats two pair in poker hands.
Three aces in poker does not beat a small straight. A small straight beats three of a kind and two of a kind.
Three kings and two nines is a full house, three aces is a three of a kind. A full house always beats a three of a kind.
Two pair works like this, the higher pair determines who is the winner. Suppose I have two pair Aces and fives, that means I beat all two pair that have kings as the higher pair, and queens etc. So Aces and fives beats Kings and queens. Now, if there is tie then the second pair comes in, so Aces and fives loses to Aces and sevens.
Depends what card game it is.
The pair of queens beat the pair of tens, the nine and the ace are irrelevant. Queens are higher ranked than tens.