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Inductor acts like a open circuit to DC at t=0 i.e at instant of closing the switch. Because it does not allow sudden change in current. Refer v= L di/dt. As t-> infinity, inductor acts like a short circuit(if pure).

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11y ago
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13y ago

Only initially, because an inductive load resists a change in current. At equilibrium, however, an inductive load will present a near short circuit to a DC supply.

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Q: Does an inductive load affects the dc power supply?
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