We did this experiment in class, the more batteries added, the brighter the bulb will become!
The brightness of three bulb would be mare than one
Nothing. The reason a circuit works is that there is an imbalance between the positive and negative (cathode and anode) ends of the battery. two positive ends wouldn't move anything.
When you start at the negative end of the battery, you start to lose electrons and the circuit is closed.
the brightness of the bulbs would decrease because the cell would have to supply more power.
Provided that the power supply is reasonably well regulated, the failureor removal of one device in a parallel circuit has no effect on the others.
The brightness of three bulb would be mare than one
It wil be on
Nothing will happen. There has to be a complete a circuit for the battery to function thus allowing for the flow of electricity.
ANSWER: The brightness of both bulbs will decrease. If the bulbs are identical the current will decrease to 0.2 Amps. This is a simple series resistive circuit, the more bulbs you add in series both the amperage and bulb brightness will continue to go down.
Nothing. The reason a circuit works is that there is an imbalance between the positive and negative (cathode and anode) ends of the battery. two positive ends wouldn't move anything.
When you start at the negative end of the battery, you start to lose electrons and the circuit is closed.
the brightness of the bulbs would decrease because the cell would have to supply more power.
You would short out the battery. If it was a car battery capable of 300 amps and the wire was big enough, the battery could explode.
Nothing special should happen. What matters for the bulb is the voltage difference between its ends.
Provided that the power supply is reasonably well regulated, the failureor removal of one device in a parallel circuit has no effect on the others.
would discharge in 18 hours
The brightness of star will decrease as you observe it from farther away.