yes because ionization energy increases up and to the left on the Periodic Table. and fluorine has the highest ionization energy because it is so close to becoming a noble gas it tears off electrons from everything to complete the octete
Bromine has less valence shells than lead making the distance between its valence electron and its nucleus less than that of lead. This means that there is greater attraction between the nucleus and electron for bromine and it requires a higher ionisation energy to remove its electron.
because neon is a noble gas which has stable electronic configuration ,but this is not the same in case of fluorine.This means we have to give high energy to gaseous neon atom to ionise it.
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yap
In general, ionization INCREASES as you move to the right and up in the periodic table, making P (Phosphorus) higher than Ca (Calcium).
Bromine has the highest.
Bromine has because the ionization energy increases as you move across and decreases as you move down.
Ionization energy decrease down the group.So in halogens,Fluorine has highest 1st ionization energy.
Because fluorine's size is lower than that of iodine, it has a greater ionization energy than iodine. Fluorine, on the other hand, appears to have a smaller shielding effect. As a result, fluorine's nucleus attracts more valence electrons than iodine's.
Halogens, specially fluorine
The reason why fluorine has a higher ionization energy level than oxygen is because it is closer to the nucleus than is oxygen, therefore, it will take more energy to pull electrons from the nucleus.
Bromine has less valence shells than lead making the distance between its valence electron and its nucleus less than that of lead. This means that there is greater attraction between the nucleus and electron for bromine and it requires a higher ionisation energy to remove its electron.
In the periodic table of elements, fluorine and iodine are in the same column, but fluorine is in the second, iodine in the fifth row. That means fluorine has only nine electrons flying around in orbitals while iodine has 53 of them. Ionization is the called a process during which a single electron is abstracted - we're now talking about the 1st ionization energy, which is much higher for fluorine. Well, as it only has nine electrons scattered in the orbitals (but according laws, of course), they do not really influence the repelling - attracting actions between the positive center and the other electrons beside them. For iodine with 53 electrons, they really do interfere with the attraction of other electrons AND as the outmost electrons (which are the ones taken away by ionization) are in those orbitals which are at the biggest distance to the center - for 53 electrons the outmost orbitals is at a much bigger distance... both results in a smaller attraction of the electrions at max distance from the center... so for iodine you need less energy to perform ionization.
The energy required to remove electron from atom are called ionization energy. Larger atom or molecule have lower ionization energy and molecule have higher ionization energy.
because neon is a noble gas which has stable electronic configuration ,but this is not the same in case of fluorine.This means we have to give high energy to gaseous neon atom to ionise it.
Potassium has a higher ionization energy than cesium.
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