Yes. With no gravity, the ball would only bounce once and never come back down. Of course, that assumes that something -- some net force -- acted on the ball and caused it to accelerate toward the ground in the first place. Moreover, if the ball has something to bounce on, then there must be another mass present, which means that there is a gravitational attraction between the ball and whatever it's bouncing on.
Gravity is proportional to mass; the more massive an object is, the greater its gravity. The greater the gravitational field, the greater the acceleration due to gravity. For example, the acceleration due to gravity on Earth is 9.8 meters per second squared, whereas it's only 1.6 m/s2 on the moon, which has only about one-sixth the mass of Earth. The ball would fall more slowly on the moon than on Earth, and the time between successive bounces would be greater (assuming equal initial heights).
It would also go into the sun and move around the sun and burst. Thus, causing a nuclear explosion reaching into the earth's core. DO NOT bounce a ball on top of a car on a sunny day, for while the sun is reflecting its heat on the car, multiple force repelling on it will cause a greater chance of dent thus causing the ball to pop while the steam shall come forth and out through the available holes in the ball. In this case, IT WILL POP! Oh, and NEVER eat pie for breakfeast...
The question is a little ambiguous, but essentially depends on how close the ball is to what is attracting it, the mass of the other object, and how accurately you would like to measure the force on the ball. For all intents and purposes, the short answer is no, the shape doesn't affect the gravity on the ball. For the most part, if the earth is attracting the ball, and the ball is very close to the earth, then it is probably more useful to model the earth as an infinite plane, and to say the force near this infinite plane is constant with respect to distance. If the ball were a satellite orbiting the earth, i would say it might be better to model the earth as an oval, with a quadrupole potential, so it would be best to look at the 1/r^4 force with angular dependence, but this term would still be small compared to the 1/r^2 term, and would die out quickly.
so, yes the shape does affect gravity on a ball, depending on your length scales.
Without gravity, the thrown ball would continue in a straight line, eventually leaving Earth.
Without gravity, the thrown ball would continue in a straight line, eventually leaving Earth.
Without gravity, the thrown ball would continue in a straight line, eventually leaving Earth.
Without gravity, the thrown ball would continue in a straight line, eventually leaving Earth.
yes because the more the air the higher the ball will bounce and the less the air and the lower the balls will bounce
It's not the weight on it's own, it's the density, which is a factor of both weight and size.
Without gravity, the thrown ball would continue in a straight line, eventually leaving Earth.
The height from which it falls, the smoothness of the surface off which it bounces and the elasticities of the ball and the surface from which it rebounds.
invisable hobos
The gravitational pull affects it more or less uniformly. There are very, very slight differences caused by the height of the throw and the width of the ball but, compared to the distance from the centre of the earth, these distances are tiny and so have no effect.
Just as the moon orbits the earth because of the earth's gravitational pull, the moon has its own gravitational pull. While it isn't enough to greatly affect the Earth's movement, it does affect the earth's oceans.
The moon affect the ocean tides because of the gravitational pull that the moon has. Where the is a high tide, the moon is pulling the water toward it's gravity. The water on the opposite side of Earth, will pull away from the moon.
uranus's gravitational pull is 91% or earth's.
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gravitational pull
No.
how does the moons gravitational pull affect me if i was on the beach
It has a minor gravitational pull on it, but it will barely affect it.
because of the gravitational pull of the moon
The earths gravitational pull would effect the ball so that once it reaches a certaion height it wouold fall back to earth. It prevents the ball leaving earths atmosphere.
When the pull is stronger, they move quicker.
When the pull is stronger, they move quicker.
Earth's gravitational pull on the red ball is greater than on the blue ball.
The gravitational pull affects it more or less uniformly. There are very, very slight differences caused by the height of the throw and the width of the ball but, compared to the distance from the centre of the earth, these distances are tiny and so have no effect.
a ball can never bounce over the height from which it was bounced unless u aplly a force. The factors that affect the bounce of a dropped ball include the height from which it is dropped; the force applied to it, if any, when dropped; the acceleration of gravity, which is different depending upon what planet you're one; the elasticity of the ball; the density of the atmosphere, which affects "air resistance"; and the rigidity and elasticity of the surface on which the ball bounces. weight also affect the bounce height.
i really dom kn