Yes. The energy is given by plank's constant times the frequencie of the photon (remember that light is both particle and wave). So since blue light has higher frequency than green light, it is more energetic.
Electromagnetic radiation, or radiowaves, have varying degrees of power based on the power delievered to the final stage of the amplifier of a given system.
Small transmitters are available for any frequency, as are large units. A 50,000 watt A.M. broadcast transmitter has far more power then your 2.5 ghz cell phone.
What does matter is the bodies ability to absorb radiation. As wavelength increases, so does the ability of our body to absorb this energy. Microwave ovens work because the signal is so high (in frequency) that the material inside the oven gets hit with the waves more then they would by low frequencies.
Yes, higher energy light has a higher frequency than lower energy light.
We might equate the frequency of light with its energy. The higher the energy, the higher the frequency, and vice versa. As we move up the electromagnetic spectrum above visible light, we see higher frequency (which simultaneously means shorter wavelength) light like ultra-violet light, X-rays and gamma rays. All these forms of light have energies higher than that of visible light.
The photon's energy is completely defined by its frequency, regardless of
what kind of source it came from, or whether it happens to be in phase with
other photons going in the same direction, or whether or not there are also
photons with different frequencies in the neighborhood.
No the photon of violet light has more energy than photon of photon of green light.
Yes, the amount of energy a photon has is related to it's frequency as follows:
E=hf,
where h is plank's constant.
It depends on the brightness of the light, if the low frequency light is brighter then its yes.
The difference is their frequency (wavelength). The higher frequency (shorter wavelength)
electromagnetic waves carry higher energy.
No, the speed of light is constant for everyone everywhere. This includes all light, even that of a different wavelength or frequency.
No. The energy of a photon is directly proportional to its frequency.
The konstant of proportionality ist Planck's Konstant.
A photon is a theoretical particle of light.The energy of a photon is directly proportional to the frequency of the light.E = hνwhere E = energy of the photonh = Planck's constant = 6.63 × 10-34 m2 kg s-1ν = frequency of the lightNote: ν in the equation above is not the English letter 'v' but the Greek letter 'nu' (pronounced new). (see related link)
An electron has dropped from a higher energy state to a lower one. The photon emitted has precisely the same energy as was lost by the electron.
The types of electromagnetic radiation in order of decreasing energy per photon is gamma rays, visible light, microwaves, and radio waves. All of the rays include cosmic rays, gamma rays, x-rays, ultra violet light, visible light, infrared light, microwaves, and radio waves.
Atoms of certain elements give off light of characteristic color when heated to high temperature since the electrons induce to absorb energy, jumps to the excited energy state called quantum jump and then returns to their ground state. The amount of energy in the photon determines its color.
When a chlorophyll molecule absorbs light, the process of photosynthesis, or the transfer of light into sugar, begins. Chlorophyll is a green liquid inside one part of a plant cell: the chloroplast. When light hits the chlorophyll molecule, it becomes excited. This energy passes through other chlorophyll molecules, and into the reaction center of Photosystem II: this is the location of the first stage of photosynthesis, and the electron transport chain. For each photon of light that enters and excites a chlorophyll molecule, one electron is released from the reaction center of Photosystem II. When two electrons are released, they are transferred to Plastoquinone Qb, a mobile carrier, which picks up two protons and starts moving towards the Cytochrome b6f complex. Cytochrome b6f, like Photosystem II, is a complex where photosynthesis processes occur.
The energy of a photon is correlated with its wave frequency - and gamma rays are by definition very high frequency photons compared to red light photons.
Cosmic Rays/High Frequency Gamma Rays
wavelength : wavelength is the distance from crest of one wave to the crest of next frequency : the number of waves that passes a given point in one second energy : the amplitude or intensity of a wave energy and frequency is directly proportional to each other when energy is high frequency is also high wavelength and frequency or energy is inversly proportional to each other when wavelength is high frequency or energy is low
High-energy photons correspond to short-wavelength light while low-energy photons correspond to long-wavelength light. In short, the answer is red. For short-wavelengths (high energy photons) it would appear blue.
The meaning of a high frequency wave is a shorter wavelength.For electromagnetic waves in general (including light):* At greater frequencies, you get shorter wavelengths.* At greater frequencies, you get more energy per photon.
This is a tricky question because there is more than one form of energy in light. There is the energy that each particle of light (the photon) has and there is group energy which is the sum total of all the photon energy as they travel as a group (like in a laser beam). But the good news is that the answer is FALSE for both the photon and group energies. Photon energy depends on the photon fundamental frequency. And the higher the energy the bluer the color, which can run from red to violet. Those photons in the violet color have higher energy than photons in the red color frequency. And group energy is just the sum of all the photon energies in a group, like a light beam from your flashlight (aka, torch). So for a given mix of photons, the more photons in the group the higher is the group energy level. What we call light intensity (e.g., bright or dim) depends on the group energy with high energy equating to high intensity.
Yes, due to the energy of photons/electromagnetic particles being determined by the equations below: E= hv=hc(1/v)= hc/wavelength. Where E= energy, v= frequency in Hz, h= Planck's constant, c= speed of light Electrons have a very short wavelength, and a very high frequency, thus they have much more energy than a beam of light.
the energy of a photon is h times f
A high energy light will have a shorter wavelength than a low energy light. If the wavelength goes down, then the frequency goes up. When calculating energy in the equation, E=hv, frequency (v) is the variable, not the wavelength. So in the equation, if you wanted a more energy (E), you would have the frequency be large. For the frequency to be big, then the wavelength has to be low.
It is not meaningful to talk about "amplitude of the visible light spectrum". One might think that more intense light would mean greater amplitude of the light wave, but it just means more photons. "Visible light" is made up of photons. A single photon has a certain quantifiable energy, and that energy is discussed in terms of frequency or wavelength. A photon with low frequency (towards the red end of the visible light spectrum, for instance) is less energetic than a photon with high frequency (towards the blue end and beyond). For all intents and purposes, the amplitude of a photon wave-packet could be said to be of "unit amplitude", the amplitude of light.
A photon is a theoretical particle of light.The energy of a photon is directly proportional to the frequency of the light.E = hνwhere E = energy of the photonh = Planck's constant = 6.63 × 10-34 m2 kg s-1ν = frequency of the lightNote: ν in the equation above is not the English letter 'v' but the Greek letter 'nu' (pronounced new). (see related link)
High energy light has a small wavelength, and a high frequency.