In the unlikely event you find yourself in a freely-falling elevator, then the relative motion of the pencil is among the least of your concerns.
If the pencil were hovering, then both you and the pencil are in free-fall.
A condition that is not permanent for you and me, and it will eventually stop.
This is commonly referred to as zero gravity, but should be called zero net gravity, for in your space station, gravity still acts - but it is exactly balanced out by centrifugal force. If gravity actually became zero, then your space station would speed off into space.
5*9.8 = 49 metres per second.
That's the force that engineers call the "weight" of the elevator car. As long as the elevator stays on Earth, its weight is constant, whether it's rising, falling, stopped, or out of order. On or near the Earth's surface, the weight of 1,140 kilograms of mass is about 11,180 Newtons (2,513.3 pounds).
If the body is freely falling, this sum will remain constant.
Yes, mass is an intrinsic property of matter. However a freely falling object will experience no weight.
No effect whatsoever. Any two freely falling bodies fall with the same acceleration when dropped in the same place on the same planet. That includes any two objects falling on Earth. Someone is sure to jump in here and point out that objects with different mass don't fall with equal accelerations on Earth, and that's because of air resistance. They may even go on to provide answers to other questions that were not asked, such as a treatise on terminal velocity. All of that is true, even if confusing. This question stipulated that the bodies in question are "freely fallling". Bodies that are falling through air are not freely falling.
none. when there is gravity T=2pi square root of L/g but in a freely falling elevator, there is no accelerate so it doesn't have period the answer is none
0.7848 meter
only if it equaled acceleration due to gravity (about 9.8 (m/s)/s)
5*9.8 = 49 metres per second.
That's the force that engineers call the "weight" of the elevator car. As long as the elevator stays on Earth, its weight is constant, whether it's rising, falling, stopped, or out of order. On or near the Earth's surface, the weight of 1,140 kilograms of mass is about 11,180 Newtons (2,513.3 pounds).
That's the force that engineers call the "weight" of the elevator car. As long as the elevator stays on Earth, its weight is constant, whether it's rising, falling, stopped, or out of order. On or near the Earth's surface, the weight of 1,140 kilograms of mass is about 11,180 Newtons (2,513.3 pounds).
If the body is freely falling, this sum will remain constant.
Force = mass * acceleration Since the only force acting on the elevator is gravity, the force is 1000*9.81 = 981N Towards the ground Note that it is essential to put the direction that the force is acting as it is a vector quantity.
Yes, mass is an intrinsic property of matter. However a freely falling object will experience no weight.
No effect whatsoever. Any two freely falling bodies fall with the same acceleration when dropped in the same place on the same planet. That includes any two objects falling on Earth. Someone is sure to jump in here and point out that objects with different mass don't fall with equal accelerations on Earth, and that's because of air resistance. They may even go on to provide answers to other questions that were not asked, such as a treatise on terminal velocity. All of that is true, even if confusing. This question stipulated that the bodies in question are "freely fallling". Bodies that are falling through air are not freely falling.
Velocity
The equation of motion is not modified. Net force = mass x acceleration, whether freely falling or not.