To determine the concentration of Br ions, we can use the solubility product constant (Ksp) expression for AgBr, which is equal to [Ag+][Br-]. Given that the [Ag+] is 1.3x10-6 and the Ksp for AgBr is 5.2x10-23, we can rearrange the equation to solve for [Br-]. Thus, [Br-] = Ksp/[Ag+] = (5.2x10-23) / (1.3x10-6) = 4x10-17. Therefore, the Br- ion concentration is 4x10-17.
No. Ksp can be used for metals as well, such as lead (Pb). The Ksp for Pb is often very small, but increases with increasing temperature.
Ksp = [Ag+]3[PO43-]
the higher the Ksp value the more soluble a compound is.
No, it can be negative.
If the ion product concentration is greater than the Ksp value a precipitate will form. If it equals the Ksp the solution is saturated and no precipitate forms.
It will decrease the Ksp
To determine the concentration of Br ions, we can use the solubility product constant (Ksp) expression for AgBr, which is equal to [Ag+][Br-]. Given that the [Ag+] is 1.3x10-6 and the Ksp for AgBr is 5.2x10-23, we can rearrange the equation to solve for [Br-]. Thus, [Br-] = Ksp/[Ag+] = (5.2x10-23) / (1.3x10-6) = 4x10-17. Therefore, the Br- ion concentration is 4x10-17.
Ksp= [Products]^mole ratio so Ksp=[Ag+][NO3] Since you didnt provide any numerical values, that's as far as you can go. You can look for known Ksp values at certain temperatures in some AP Chemistry books or online.
for Ni(OH)2, Ksp=6.0*10^(-16)
ksp = [Ca+2][OH-]^2
No. Ksp can be used for metals as well, such as lead (Pb). The Ksp for Pb is often very small, but increases with increasing temperature.
Ion product < Ksp Unsaturated solution Ion product = Ksp Saturated solution Ion product > Ksp Supersaturated solution
A precipitate will form
KSP means Kulang Sa Pansin that means when your talking to someone but she/he is not talking to you
solubility = [Ba2+]= 80 x 10-6 M When BaSO3 dissolves it gives equal concentration of Ba2+ and SO32-, so Ksp = [Ba2+][SO32-] = 6.4 x10-9
Ksp = [Ag+]3[PO43-]