answersLogoWhite

0


Best Answer

no

User Avatar

Wiki User

11y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Does power decrease when adding resistors in parallel circuit?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Electrical Engineering

How do you find resistance in a parallel circuit?

resistance inparallel decrease in value proportionally two resistance can be calculated as R1XR2/SUM OF R1+R2. many values can be calculated as a fraction 1/r+1/r2+1/3 ....and take the total sum reciprocal


How is electrical resistance decreased?

Ways to reduce electrical resistance: increase the diameter of the conductor, decrease or increase the temperature of conductor (depending on its thermal characteristics), decrease the length of the conductor. A change in the material out of which the conductor is made can decrease resistance, too. And there is the phenomenon of superconductivity. In a simple circuit the resistance can be lowered by adding resistors in parallel. The total circuit resistance will then decrease. You can also reduce resistance by substituting resistors of lower value, or by adjusting a potentiometer, or pot, to a lower value.


Does adding resistors in series increase or decrease the overall resistance of a circuit?

Resistance in series adds together. two 100 ohm resistors in series are equivalent to one 200 ohm resistor. to make an equation out of it ( even though it is simple) you can say: Rtotal=R1+R2+R3...+Rn


In a series circuit each device that is added to the circuit decreases the what?

Depends on the device. If it is a resistor and you have a fixed voltage then the circuit will obey Ohms law. Voltage = Current x Resistance. So if R increases by adding more resistors in series and the voltage is constant, the current will decrease.


What will adding resistance to series circuit cause?

A decrease in current.

Related questions

How do you find resistance in a parallel circuit?

resistance inparallel decrease in value proportionally two resistance can be calculated as R1XR2/SUM OF R1+R2. many values can be calculated as a fraction 1/r+1/r2+1/3 ....and take the total sum reciprocal


How is electrical resistance decreased?

Ways to reduce electrical resistance: increase the diameter of the conductor, decrease or increase the temperature of conductor (depending on its thermal characteristics), decrease the length of the conductor. A change in the material out of which the conductor is made can decrease resistance, too. And there is the phenomenon of superconductivity. In a simple circuit the resistance can be lowered by adding resistors in parallel. The total circuit resistance will then decrease. You can also reduce resistance by substituting resistors of lower value, or by adjusting a potentiometer, or pot, to a lower value.


Does adding resistors in series increase or decrease the overall resistance of a circuit?

Resistance in series adds together. two 100 ohm resistors in series are equivalent to one 200 ohm resistor. to make an equation out of it ( even though it is simple) you can say: Rtotal=R1+R2+R3...+Rn


What happens to the resistance in a parallel circuit when more light bulb is added?

Adding anything(yes,even a superconductor) to a any circuit adds resistance, especially devices that are by there very nature high resistors


What does adding more resistors to a paralles circuit decrease the equivalent resistance of the circuit?

This is a direct consequence of Ohms Law. Since each new resistor connected in parallel will allow more current to flow, the resistance of the circuit must be lower. R = E/I. Since I (current) has increased, and the voltage E is still the same, it follows that R (resistance) must be smaller. That's the way Ohms Law works.


How is total resistance calculated in a series circuit?

If the circuit consists of resistors only, you simply add the values of all the resistors, in ohms.


In a series circuit each device that is added to the circuit decreases the what?

Depends on the device. If it is a resistor and you have a fixed voltage then the circuit will obey Ohms law. Voltage = Current x Resistance. So if R increases by adding more resistors in series and the voltage is constant, the current will decrease.


What will adding resistance to series circuit cause?

A decrease in current.


When you short out a resistor in a parallel circuit why does the current lower?

The total resistance of a set of resistors in parallel is found by adding up the reciprocals of the resistance values, and then taking the reciprocal of the total. By removing a resistor the total current will lower. If you short out the parallel circuit as suggested it will take out the fuse that should be protecting the circuit.AnswerShorting-out a resistor in a parallel circuit, will act to short out the entire circuit, therefore, significantly increasing, not lowering, the current! And, as the previous answer indicates, this short-circuit current will operate any protective devices, such as a fuse.In a parallel circuit current does not lower but it will be increase if shorting-out one resistor in the two resistor parallel circuit, the circuit will become very low resistive and the larger current will flow through the short path.


What would be the affect on the overall current in a parallel circuit if additional resistance was added in parallel?

Suppose we have a circuit containing a 15 volt battery and two 10 ohm resistors, and those resistors are in parallel. The total resistance of the two 10 ohm resistors = 5 ohms (1/10 + 1/10 = 1/5). Therefore the total amount of current flowing from the battery = 15/5 = 3 amperes. Adding a third 10 ohm resistor in parallel to the other two means that the total resistance of the circuit is now 3.333 ohms (1/10 + 1/10 + 1/10 = 1/3.333. Therefore the total current flowing from the battery = 15/3.33 = 4.5 amperes. Parallel resistances can be thought of as separate circuits. If we had a circuit containing a 15 V battery and a 10 ohm resistor, then 1.5 amperes would flow around that circuit (V = IR, 15 =10 x 1.5). If you keep adding 10 ohm resistors in parallel then the total current flowing out of the battery will step up accordingly: 1 resistor draws 1.5 amps, 2 draws 3 amps, 3 draws 4.5 amps, 4 draws 6 amps etc.


In a series circuit of three bulbs adding another one will?

Do nothing. But in a parallel circuit, all the bulbs will get dimmer.


What happens to the current through a series circuit as more resistors are added in series?

If the bulbs are in a series circuit the voltage drops at each bulb drops as additional bulbs are added. In a parallel circuit the voltage is constant no matter how many bulbs are added.