No it does not, as a raindrop falls to earth it will gradually slow due to the changing terminal velocity. As a raindrop falls, water will evaporate from it causing the mass to decrease faster than the size and surface area. this will leave the raindrop with a higher surface area to mass ratio. Since air resistance is related to surface area and mass, the smaller raindrop will have more air resistance for its mass and will fall slower.
Is zero. No change in velocity means no acceleration.
If the velocity is constant then there is no acceleration. The acceleration is zero.
They reach their terminal velocity.
The viscosity of air provides a drag force on a raindrop and keeps it from falling with the acceleration of gravity. When a drop is falling (assuming it does not combine with other drops in the process) it will reach a terminal velocity which depends on its diameter. The larger the diameter the larger the terminal velocity. Specifically, the terminal velocity is proportional to the square root of the diameter of the drop. Big rain drops fall faster than small rain drops. See related links for details and equations.
If the raindrop is falling at a constant speed, then it has reached terminal velocity. This happens when the downward force (due to gravity) is the same as the upward force due to friction. As such the net force acting on the rain drop is 0.
Considering the rain droplets as spherical body. We have two forces acting on the rain drop when it is falling through the sky, namely the resistance force due to friction(drag force)upwards and its weight downwards. Th rain drop falling from such distance attain a terminal velocity while falling i.e their speed becomes constant after sometime. This happens when the drag force equals the weight of drop,, this happens because drag force increases with velocity of the drop. Drag force= .5*rho*v2*A(frontal area)*Cd(coefficient of drag) Weight=m*g=rho*volume of spherical drop=rho*4/3*r3. When we equalize it, we get the Terminal Velocity(v) varying directly as sqr of r(radius of drop) So larger drop means, larger terminal velocity and hence less time taken for falling. So larger rain drop falls faster.
This is not a simple question and not enough information is provided to answer it. Among other things it depends upon the time it takes to reach terminal velocity and the terminal velocity depends on the various drag forces operating which in turn will depend on other variables such as initial height, wind speed, temperature, humidity, etc. You could calculate the velocity of any object falling in a vacuum if the acceleration due to gravitational force remains constant throughout the fall. v=v0+at where vo=initial velocity (probably zero if the object is initially at rest), a is the acceleration due to gravity (9.8m/s2) at or near the surface of the earth, and t is the time of fall.
because
The air resistance will increase to the point where it counters the downward acceleration.
Rain.
the reason why is because of the shape and weight if the rain drop. the weight of a rain drop is less than a gram and the shape of one when falling from the sky, has a lot of drag. this means that the terminal velocity of a rain drop is very slow
Rain fall is not always constant. That's how they get there water
consider a sphere moving through a viscous medium the fluid layer in contact with the sphere is moving with same velocity but the layer far away is at rest. This makes a relative motion to be setup.viscous force acts on this drop.The backward force is proportional to the speed of the drop.at a stage the viscous force balances the downward force.hence the body moves with a constant velocity called terminal velocity.