No. Regardless of where you throw the ball, its vertical acceleration is
always roughly 9.8 m/s2 downward after it leaves your hand, and its
horizontal acceleration is always roughly zero.
The reason we have to say "roughly" is because of the air resistance
that the ball runs into.
The acceleration of cart is dependent on angle of inclination. So angle will change acceleration. mgSin(theta)
You will need angle of inclination and observe the object motion. Force pushing object up inclined plane is force act against gravity, if the object move at acceleration then the force is more than gravity. You will need to transform distance travel to height using trigonometry from known angle of inclination and calculate acceleration against direction of gravity. Add this extra acceleration to gravity and time the mass you get the force. So I was just wondering if you could expand on that or tell me an equation that if I only know the angle, the acceleration that they are pushing the block up at , the force of gravity which most people know (9.81 m/s2) and the mass of the block then i could get kinetic force thx Additional comment 1. Gravity pull down that is mg and incline at angle A 2. Force is on direction of incline plane and against gravity at mg sin(A) 3. At additional acceleration in direction of incline plane e.g. a this excess force is m.a 4. Net force input is m(a+g.sin(A)) if no acceleration observe then it mean a = 0 Thanks
9.8 meters per seconds squared in the downward direction.
The only force acting on the object (let's say a cart) that is released at a certain inclination (30 degrees) is gravity. If we follow the formulas: Fgx=mgSinO Fnet=ma Fgx=Fnet Therefore: mgSinO=ma and you can simplify this formula to: gSinO=a m= mass g= gravitational force (9.8m/s^2) SinO= sin of angle (Sin30 degrees) a=acceleration
This is total internal reflection where the angle of refraction is 90 degrees and its incident angle would be the critical angle(angle of incident for which the angle of refraction is 90).... This hapens when the angle of incidence is in a medium more dense than the angle of refraction's medium
either 00 or 1800A straight angle is an "angle" that doesn't affect the direction of a line. A 00angle sends the line in the opposite direction.
The contribution of the acceleration of gravity in the direction of motion increases as the angle of the incline increases. Or in other words, as the angle between the direction of motion and the force of gravity goes to zero, the acceleration of the object goes to the gravitational acceleration. a = g cos(theta) Where theta is the angle between the direction of motion and verticle, which is in fact (theta = 90 - angle of the incline)Where a is the acceleration of the object down the incline plane and g is the acceleration due to gravity. Theta is the angle between the direction of motion of the accelerating object and the acceleration of gravity. Initially, the angle between a and g is 90 degrees (no incline) and therefore g contributes nothing to the objects acceleration. a = g cos(90) = 0 As the angle of the inclined is increased, the angle between a and g approaches zero, at which point a = g. With no other forces acting upon the object, g is its maximum acceleration.
The ratio is the M/cos(x). where M is the mass on which the force is acting and x is the angle between the direction of the force and the direction of the acceleration.
In a polygon, it is the next angle along - in either direction.
The charged particle moves like it accelerated around the field and along the field:F= - qV.B + qVxB = ma = -qvbcos(angle) + nqvbsin(angle) where n is perpendicular to the the plane of V x B. The acceleration a= F/m = (-cos(angle) + n sin(angle))qvB/m is a quaternion acceleration consisting of a scalar and a vector.The motion of the particle is an ellipse inclined to the direction of the field. If the angle is 90 degrees, the ellipse is a circle and is perpendicular to the field direction.
Inclination Effects on Lift. As a wing moves through the air, the wing is inclined to the flight direction at some angle. The angle between the chord line and the flight direction is called the angle of attack and has a large effect on the lift generated by a wing.
Extrapolate the experimental values of acceleration, vs. angle of the incline, to find the acceleration when the angle of inclination = 90 degrees. The acceleration at 90 degrees will equal 9.81 m/s/s, since this is the free-fall acceleration.
The acceleration of cart is dependent on angle of inclination. So angle will change acceleration. mgSin(theta)
right angle
Yes. The angle is the direction of the vector, so if the angle changes, the direction changes.
You will need angle of inclination and observe the object motion. Force pushing object up inclined plane is force act against gravity, if the object move at acceleration then the force is more than gravity. You will need to transform distance travel to height using trigonometry from known angle of inclination and calculate acceleration against direction of gravity. Add this extra acceleration to gravity and time the mass you get the force. So I was just wondering if you could expand on that or tell me an equation that if I only know the angle, the acceleration that they are pushing the block up at , the force of gravity which most people know (9.81 m/s2) and the mass of the block then i could get kinetic force thx Additional comment 1. Gravity pull down that is mg and incline at angle A 2. Force is on direction of incline plane and against gravity at mg sin(A) 3. At additional acceleration in direction of incline plane e.g. a this excess force is m.a 4. Net force input is m(a+g.sin(A)) if no acceleration observe then it mean a = 0 Thanks
9.8 meters per seconds squared in the downward direction.