On its volume.
In the general case, these are quite unrelated; the buoyant force is related to the object's volume, not its weight. Or the part of the volume that is submerged in the liquid or gas. However, if the object is freely floating, then the buoyant force will be equal to its weight.
As soon as an object is completely submerged in the liquid, displacing the maximum volume of liquid.
The amount of buoyant force is equal to the weight of the displaced water. The VOLUME of the displaced water is equal to the part of the solid that is submerged - thus, the buoyant force is equal to this volume, times the density of the water.
Submerge the object in a known volume of liquid within a container with graduation markings. Carefully turn the object to release and trapped gases from concavities. Measure the new volume of liquid with the object submerged and subtract the original volume. The difference is the volume of the irregularly shaped object. If the object is buoyant, choose a lower density liquid or hold the object beneath the surface with a rod or rods, noting the length of rod(s) submerged at the time of the second fluid measurement, then subtract the volume of rod submerged from the difference in the two fluid volumes.
a submerged object displaces liquid which is equal to its volume
volume
The buoyant force is zero when the object is just touching the liquid. As the object displaces more volume, the buoyant force increases until the object is completely submerged. Once the object is submerged, it doesn't matter how deep it is, the buoyant force remains constant.
That completely depends on the object's volume (which you have not mentioned). The buoyant force on it is equal to the weight of an equal volume of water.
In the general case, these are quite unrelated; the buoyant force is related to the object's volume, not its weight. Or the part of the volume that is submerged in the liquid or gas. However, if the object is freely floating, then the buoyant force will be equal to its weight.
As soon as an object is completely submerged in the liquid, displacing the maximum volume of liquid.
The buoyant force is equal to the amount of water displaced. Multiply the volume of the object by the density of water - then convert that to a force (at about 9.8 newton/kilogram).
The amount of buoyant force is equal to the weight of the displaced water. The VOLUME of the displaced water is equal to the part of the solid that is submerged - thus, the buoyant force is equal to this volume, times the density of the water.
Submerge the object in a known volume of liquid within a container with graduation markings. Carefully turn the object to release and trapped gases from concavities. Measure the new volume of liquid with the object submerged and subtract the original volume. The difference is the volume of the irregularly shaped object. If the object is buoyant, choose a lower density liquid or hold the object beneath the surface with a rod or rods, noting the length of rod(s) submerged at the time of the second fluid measurement, then subtract the volume of rod submerged from the difference in the two fluid volumes.
a submerged object displaces liquid which is equal to its volume
The volume of the submerged object.
A submerged object will displace its own volume of the liquid it is submerged in.
It is not the weight of the immersed object but the volume of the object would affect the buoyant force on the immersed object because the buoyant force is nothing but the weight of the displaced liquid whose volume is equal to that of the immersed object.