volume
The conclusion of the Archimedes principle is simply that the upward buoyant force that is experienced by a body immersed in a fluid, is equivalent to the weight of the fluid that the body displaces. This allows the volume of an object to be measured by measuring the volume of liquid it displaces after submerging. For any immersed object, the volume of the submerged portions equals the volume of fluid it displaces.
The object will sink in the fluid.
Then the object will sink.
an object is immersed in a fluid is buoyed up by a force equal to the weight of the fluid displaced by the object. This became known as Archimede's principle. The weight of the displaced fluid can be found mathematically. The fluid displaced has a weight W = mg. The mass can now be expressed in terms of the density and its volume, m = pV. Hence, W = pVg.
TRUE
On its volume.
It is not the weight of the immersed object but the volume of the object would affect the buoyant force on the immersed object because the buoyant force is nothing but the weight of the displaced liquid whose volume is equal to that of the immersed object.
The same object is more buoyant in a denser fluid, and is more likely to float, than in a less dense one. That's why tennis balls float in water but not in air.
The buoyant force doesn't depend on the object's weight. It depends on theobject's volume, which the question doesn't reveal.
That completely depends on the object's volume (which you have not mentioned). The buoyant force on it is equal to the weight of an equal volume of water.
In the general case, these are quite unrelated; the buoyant force is related to the object's volume, not its weight. Or the part of the volume that is submerged in the liquid or gas. However, if the object is freely floating, then the buoyant force will be equal to its weight.
The buoyant force on an object depends only on the weight of the fluid displaced: Fb = Vd*ρf*g Vd may not be the volume of the object; for example: if the object is floating on the liquid surface. Also, there may be other forces acting on the object, such as its weight (Mo*g)
The buoyant force on any object in a fluid ... whether partially or fully submerged ... isequal to the weight of the fluid displaced by the object. That's related to the object'svolume, and has nothing to do with its weight.
It is called buoyant force. It is calculated by determining the volume of water displaced by the object, which is the volume of the object under water.The weight of this quantity of water is the buoyant force. It can also be calculated by knowing the depth of the object in the water, the pressure at that depth, and the area of the bottom of the object. Buoyant Force = Pressure * depth It can also be calculated by knowing the weight of the object. If an object is floating the water is supporting the object's weight. So the buoyant force = weight of object
No, but the difference between the buoyant force and the weight of the object will determine whether it floats or sinks.
More volume means that the object displaces more water. The buoyant force is exactly equal to the weight of the displaced water. Or other liquid.
If the object is floating, then the buoyant force is equal to the object's weight.