For a transformer, the turns ratio always applies between its primary and secondary windings. So the turns ratio for a three-phase transformer is the ratio of primary to secondary phase voltages, not between line voltages.
600 volts between any two wires. The phase has nothing to do with voltages, only current relationship.
They must be precisely in phase. If connected out of phase current would flow uncontrollably between the two alternators as a short circuit.
The 3 phase formula you are looking for is I = HP x 746/1.73 x E x% Eff x pf. Where I = amps, E = voltage, %Eff = percent efficiency of the motor and pf = power factor.
Phase to Phase voltageCorrection to the above answer:There is no such thing as a 'phase-to-phase' or 'phase-to-ground' voltage. The correct terms are 'line-to-line' (or 'line voltage') and 'line-to-ground' (or 'phase voltage'). Transmission-line voltages are line-to-line (or 'line') voltages.
Nominal transmission and distribution voltages are line voltages. So '66 kV' is a line-to-line voltage. Note that there is no such thing as a 'phase-to-phase' voltage -the correct term is 'line-to-line'. Using the term, 'phase-to-phase', indicates a lack of understanding of a.c., which is not uncommon! Incidentally, the symbol is 'kV', not 'KV'.
given a balance three phase, three wires system with star-connected load for which lime voltage is 230v and the impedance of each phase is (6+j8)ohm. find the line current and power absorbed by each phase.
Phase angle is defined as the angle by which the load current leads or lags the supply voltage in an AC circuit. There are numerous ways to calculate a circuit's phase angle, so there is no 'formula' as such. For example, if you know a load's resistance and impedance, or its true power and apparent power, then you can use basic trigonometry to calculate the phase angle, and so on.
600 volts between any two wires. The phase has nothing to do with voltages, only current relationship.
Line current = 1.732 x Phase CurrentCommentOnly for balanced loads.
They must be precisely in phase. If connected out of phase current would flow uncontrollably between the two alternators as a short circuit.
1) in inductor there is generation of magnetic field due to flow of current . so there is phase difference in voltage and current . 2)in capacitor there is storage of charges. there is phase diff. 3)But in case of resistor there is no such things are happend . it is only a power dissipating element.therefor there is no phase difference between current and voltage.
The formula is: current (in amps) = power (in watts) , divided by (240 times the power factor). The power factor is 1 for incandescent light or heaters, otherwise it can be assumed to be 0.75 for other loads.
Three phases conditions are: 1. there should be three wires for carrying current and voltage. 2. the current and voltages should be sinusoidal in nature i.e A.C voltages or currents. 3. phase angle should be 120 degree apart for each line voltages or current. Suppose voltage of the first line is given by: Va= Vsin(phi) Then second and third line voltages will be: Vb=Vsin(120-(phi)) and Vc=Vsin(240-(phi)) where (phi) is the phase angle and V is the supply voltages which has same magnitude in all the three phases.
Your question is not clear.There is no such thing as a 'resultant' three-phase voltage. There are three, separate, line voltages (i.e. voltages measured between line conductors) for a delta-connected supply, which are equal in magnitude to the corresponding phase voltages. For a balanced wye-connected system, there are three line-voltages (again, measured between line conductors) which are 1.732 larger than the three phase-voltages (measured between each line conductor and the neutral conductor). For an unearthed unbalanced three-phase wye-connected load (unusual, but possible), the figure of 1.732 doesn't apply; instead the relationship must be determined by vector addition.If your question means to ask how do you determine the line voltages of a wye-connected system, given a set of unbalanced phase voltages, then you must vectorially add the relevant phase voltages to determine the relevant line voltage, taking into account the sense, or direction, of each phase voltage.
In three-phase systems, we always consider individualline or phase currents, or individual line or phase voltages. In other words, we treat currents and voltages no differently from single-phase currents or voltages (i.e. we don't 'combine' them because they are three-phase quantities). So these quantities are expressed in r.m.s. values.
Add them upAnswerThere is no 'total' current in a three-phase system. The current flowing in each line (not 'phase') is considered separately. And you most definitely don't 'add them up'!
There is no 'total voltage' in a three-phase system. There are three line voltages and three phase voltages.