If you're thinking about a pendulum but not mentioning it, then no, it doesn't
Displacement is a vector quantity while distance is a scalar quantity. so in case of displacement, it depends on final position. For example:- If a man walks on a circle, then if he completes one round then his displacement will be zero because the man is at same position as start position. But, his distance travelled will not be zero; it is equal to circumference of the circle.
Yes and no.Some use "displacement" only to describe a change in the position of an object from some initial starting point to some ending point. That is, there is a distinction between "position" and "displacement." The position would be defined relative to a reference point. In that case the arrow depends only on where the particle was and where it ended up and the reference point does not matter.Others use a definition for displacement which describes the difference between an object's position and a fixed reference point. That is, how far an object is displaced from a certain point even if the object had never been at that point. A distinction between position and displacement is not made. For this latter definition, the choice of reference point will make a difference in the direction of the arrow.In physics problems one usually only cares about the changes in position (and velocity, etc) and the choice of reference point will not affect these.
Any wave oscillates about the equilibrium (rest) position with a maximum distance from equilibrium of A, which is the amplitude. This depends on the type of wave (water on pond, light, that parachute from elementary class...)
work depends on:FORCE and DISPLACEMENT. it is directly proportional to both of them. work can be calculated by the product of force and displacement. if displacement is in a certain direction to the applied force then work done is calculated by force*displacement cos(angle). work done becomes 0when:- *displacement is 0 or the initial point and final point are the same. *displacement is in perpendicular direction to force applied.
Its a path function......but DISPLACEMENT is a state function.Distance depends on the path we followed from one state to another but displacement is a straight distance so it depends upon the states.
position or displacement it depends on whether you are considering it a vector or a scalar
Displacement is a vector quantity while distance is a scalar quantity. so in case of displacement, it depends on final position. For example:- If a man walks on a circle, then if he completes one round then his displacement will be zero because the man is at same position as start position. But, his distance travelled will not be zero; it is equal to circumference of the circle.
The temperature of a reaction will entirely change th equilibrium position for any given reaction. If I'm right, as you increase the temperature, the equilibrium shifts closer to the endothermic reaction as there is more heat to consume. It may also, of course, change other properties of the substances involved in the reaction, but that depends on the chemicals.
The equilibrium of a firm depends with the elasticity of a demand curve.
It is not "necessary" for oscillation to occur in any "arbitrary" circuit. It depends on the design objectives. Please be more specific, and restate the question.
That depends on what discipline you're studying. In Physics: the maximum extent of a vibration or oscillation, measured from the position of equilibrium. • the maximum difference of an alternating electrical current or potential from the average value. In Astronomy: the angular distance of a celestial object from the true east or west point of the horizon at rising or setting. In Mathematics: the angle between the real axis of an Argand diagram and a vector representing a complex number.
Yes and no.Some use "displacement" only to describe a change in the position of an object from some initial starting point to some ending point. That is, there is a distinction between "position" and "displacement." The position would be defined relative to a reference point. In that case the arrow depends only on where the particle was and where it ended up and the reference point does not matter.Others use a definition for displacement which describes the difference between an object's position and a fixed reference point. That is, how far an object is displaced from a certain point even if the object had never been at that point. A distinction between position and displacement is not made. For this latter definition, the choice of reference point will make a difference in the direction of the arrow.In physics problems one usually only cares about the changes in position (and velocity, etc) and the choice of reference point will not affect these.
Any wave oscillates about the equilibrium (rest) position with a maximum distance from equilibrium of A, which is the amplitude. This depends on the type of wave (water on pond, light, that parachute from elementary class...)
work depends on:FORCE and DISPLACEMENT. it is directly proportional to both of them. work can be calculated by the product of force and displacement. if displacement is in a certain direction to the applied force then work done is calculated by force*displacement cos(angle). work done becomes 0when:- *displacement is 0 or the initial point and final point are the same. *displacement is in perpendicular direction to force applied.
it depends on how big your "bunny" is
Its a path function......but DISPLACEMENT is a state function.Distance depends on the path we followed from one state to another but displacement is a straight distance so it depends upon the states.
Its a path function......but DISPLACEMENT is a state function.Distance depends on the path we followed from one state to another but displacement is a straight distance so it depends upon the states.