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pressure will be halved
Because the field between plates in a capacitor is homogenous. It has the same strength in every point of the field.
The conductors of the transmission line act as a parallel plate of the capacitor and the air is just like the dielectric medium between them.A capacitor is a device used to store electrical charge and electrical energy.
You could measure it with a Capacitance meter. Or you could use the formula:In a parallel plate capacitor, capacitance is directly proportional to the surface area of the conductor plates and inversely proportional to the separation distance between the plates. If the charges on the plates are +q and −q, and V gives the voltage between the plates, then the capacitance C is given byFor further info on the total value of capacitance in series or parallel, Google it.
The reactance of a capacitor is a function of -- the capacitance of the capacitor -- the frequency of the voltage across the capacitor
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by using capacitor plates. The length,area ,thickness and type of the plate determines the amount of charge a capacitor can store.
Pursuant to Ohms Law, we can deduce that the answer is the square root of Pi divided by C*R+A.
Yes. Increasing the plate area of a capacitor increases the capacitance. The equation of a simple plate capacitor is ...C = ere0(A/D)... where C is capacitance, er is dielectric constant (about 1, for a vacuum), e0 is electric constant (about 8.854 x 10-12 F m-1), A is area of overlap, and D is distance between the plates. (This is only a good estimate if D is small in comparison to A.) Looking at this, you can see that capacitance is proportional to plate area.
it decreases...............
FOR tESTING THE SIGN OF CHARGE ON BODY, a device called GOLD LEAF ELECTROSCOPE. When the disc of a positively charged is touched with any plate of the charge capacitor. IF the divergence of gold leaf increases, then the plate is positively charged and if the divergence in the leaf decrease then the plate of the capacitor is nagatively charged.
Whichever plate is connected to the positive end of a battery.
3.42*10^-11 farad.
For a parallel plate capacitor is The poynting vector points everywhere radially outward of the volume between plates.
In a capacitor it is a build up of electrons on a plate.
the charge on the capacitor had increased.
You need more information than this to find your solution. There will be a a value for the electric field at which point the air will break down. you also need the area of one of the capacitors and the capacitence