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Assume the compound has a molar mass of 100 grams, from the information given, 32.2 grams is Calcium and 67.8 grams is Nitrogen.

You then find the moles of each, which would be moles of Ca and moles of N.

Dividing the two moles gives you the mole fraction: which we approximate to 6. This means that for every 1 mole of Ca, there are 6 moles of N, thus the answer is

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Q: Empirical formula for a compound that contains 32.2 percent Ca and 67.8 percent N by mass?
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