CH2OCO(CH2)7CH=CH(CH2)7CH3 CH2OH CH3(CH2)7CH=CH(CH2)7COONa
| | +
CHOCO(CH12)12CH3 + 3NaOH ---> CHOH + CH3(CH2)14COONa
| | +
CH2OCO(CH2)16CH3 CH2OH CH3(CH2)16COONa
Soaps make soluble in water fats an oils, forming specific micelles.
Saponification is the process of creating soap. It typically involves reacting a strong alkaline (such as sodium hydroxide, potassium hydroxide, etc.) with a fatty acid or oil. The strong base reacts with the fatty acid to create a salt with a long hydrocarbon chain left over from the fatty acid or oil. Here's the reaction (using lye as an example): (hydrocarbon chain)-COOH + NaOH --> (hydrocarbon chain)-COONa + H2O When the cation bonds with the fatty acid/oil, it creates a new substance that possess the hydrophilic properties of the lipid hydrocarbon chain as well as the hydrophilic properties of the alkali metal (the sodium atom). Therefore, it can mix with both hydrophobic AND hydrophilic substances. Thus, if you need to wash away something greasy (hydrophobic), the hydrophobic chain of the soap will mix with the greasy substance, and a polar substance (such as water) can mix with the hydrophilic end of the soap as well...allowing you to mix grease with soap with water...and wash it away.
It is not using H2S gas. It is using H2O liquid.
6C6H12O6 + 6O2 --> 6CO2 + 6H2O + 34ATP The equation shown above is the chemical equation of aerobic cellular respiration. It takes in a complex sugar, glucose, and breaks it down in order to harvest its stored up energy.
The simple scalar method of calculation is to integrate the square of the radius (r) across dm, where m is the mass. (Integral r2 dm is the equation, but we don't have an integral sign here.) Use the link to Wikipedia for the rest of the information and expansions on the "basic" equation.
Insoluble soaps are not likely to exist, they won't work when not IN water. For more you can trust on this: his process is called saponification: fat + sodium hydroxide -> Sodium salts of fatty acid (Soap) + glycerol
Soaps make soluble in water fats an oils, forming specific micelles.
You cannot represent a proportional relationship using an equation.
A quadratic equation normally has 2 solutions and can be solved by using the quadratic equation formula.
For an equation of the form ax² + bx + c = 0 you can find the values of x that will satisfy the equation using the quadratic equation: x = [-b ± √(b² - 4ac)]/2a
Gibbs-duhem-margules equation and its derivation
Saponification is the process of creating soap. It typically involves reacting a strong alkaline (such as sodium hydroxide, potassium hydroxide, etc.) with a fatty acid or oil. The strong base reacts with the fatty acid to create a salt with a long hydrocarbon chain left over from the fatty acid or oil. Here's the reaction (using lye as an example): (hydrocarbon chain)-COOH + NaOH --> (hydrocarbon chain)-COONa + H2O When the cation bonds with the fatty acid/oil, it creates a new substance that possess the hydrophilic properties of the lipid hydrocarbon chain as well as the hydrophilic properties of the alkali metal (the sodium atom). Therefore, it can mix with both hydrophobic AND hydrophilic substances. Thus, if you need to wash away something greasy (hydrophobic), the hydrophobic chain of the soap will mix with the greasy substance, and a polar substance (such as water) can mix with the hydrophilic end of the soap as well...allowing you to mix grease with soap with water...and wash it away.
You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.
It is not using H2S gas. It is using H2O liquid.
A chemical equation.
It burns to give T2O5 - that should be an easy equation to write.....
Nothing special, please balance correctly the equation.