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The answer is B. Because the voltmeter and the ammeter gives us the voltage and current respectively. and by the multiplication of both we get apparent power and by the Walt meter we get the actual power.. and the p.f. is the ratio of the apparent and actual power..
PF would likely stand for plug flow.
It depends on the power factor. If the PF = 1, then you need 75kVA. In general, kVA needed = 75kW/PF.
In exactly the same way as you do so for a single-phase load. It's the product of the power of the load, expressed in kilowatts, and the during of operation, expressed in hours. (And the symbol of kilowatt hours is 'kW.h', not 'kwh')
The most common use of pF in electronics is to denote a picofarad, which is 1x10-12 Farads. The Farad is the base unit of measurement for capacitance.
The watt meter on three phase system is the same as the one on your house except that it monitors all three phases at once. The meter base is called a 7 jaw base which monitors the three phases and the neutral. The house meter is a 5 jaw meter. The watt meter is a totalizer which keeps track to the watts consumed by the dials on the face of the meter, which gets read monthly by the power supplier.
A capacitor meter measures the value of a capacitor in pf (picofarads), nf (nanofarads), uf (microfarads) or even farads. There are a million uf in a farad, 1000 nf in a uf, and 1000 pf in a nf. A farad is a very large amount of capacity. The capacity tells you how much energy the capacitor can store from a voltage source.
Old type, analog power factor meters may be considered 2% instruments.
kW = I x E x pf/1000. Take this figure and multiply it by the amount of hours that the smoke detector is in operation. pf = power factor.
Recovery is not part of the Joint Commission key principles for effective emergency management in hospitals.
pf 69 is higher in value, than pf65.
There is no element with the symbol Pf.
Pf is the symbol for Power Factor.
No, it is not taxable
PF = Power Forward.
Posture Foundation
The answer is B. Because the voltmeter and the ammeter gives us the voltage and current respectively. and by the multiplication of both we get apparent power and by the Walt meter we get the actual power.. and the p.f. is the ratio of the apparent and actual power..