Actually, a for loop is more appropriate in this case. With while, it would be something like the following pseudocode - adapt to your favorite programming language:
function factorial(n)
result = 1
factor = 1
while factor <= n
{
result *= factor
factor++
}
return result
double factorial(double N){double total = 1;while (N > 1){total *= N;N--;}return total; // We are returning the value in variable title total//return factorial;}int main(){double myNumber = 0;cout > myNumber;cout
#include <iostream> using namespace std; int main() { int i, number=0, factorial=1; // User input must be an integer number between 1 and 10 while(number<1 number>10) { cout << "Enter integer number (1-10) = "; cin >> number; } // Calculate the factorial with a FOR loop for(i=1; i<=number; i++) { factorial = factorial*i; } // Output result cout << "Factorial = " << factorial << endl;
In GW-BASIC, you can calculate the factorial of a number using a WHILE...WEND loop. First, initialize a variable for the factorial result (e.g., fact = 1) and a counter variable (e.g., i). Then, use a WHILE loop that continues as long as i is less than or equal to the number for which you want the factorial. Inside the loop, multiply fact by i, increment i, and finally print the result after the loop ends. Here's an example code snippet: INPUT "Enter a number: ", n fact = 1 i = 1 WHILE i <= n fact = fact * i i = i + 1 WEND PRINT "Factorial of "; n; " is "; fact
// returns n! int fact(final int n) { // keep track of factorial calculation in f // f starts at n, and we will multiply it by all integers less than n int f = n; // loop from n-1 down to 2 for(int i = (n - 1); i > 1; --i) { // increase our total product f *= i; } return f; }
#include #include using std::cin;using std::cout;using std::endl;using std::tolower;long factorial(const int& N);int main(){int N = 0; //factorial of Nchar command = 'n';do{cout > N;cout
#include #include using std::cin;using std::cout;using std::endl;using std::tolower;long factorial(int N);int main(){int N = 0; //factorial of Nchar command = 'n';do{cout > N;cout
/* gcc -ansi -Wall -Wextra -pedantic -s -static 0.c -o 0 */ #include <stdio.h> int main ( ) { int n , factorial = 1 ; printf ( "enter the value of n\n") ; scanf ( "%i" , & n ) ; while ( n != 0 ) { factorial *= n ; n -- ; } printf ( "The factorial of n is\n%i\n" , factorial ) ; return 0; }
by this program you can find the factorial: #include<iostream> using namespace std; main() { int n,x,f=1; cin>> n; x=0; while(x<n) { x++; f= f*x; } cout<<"factorial is"<<f<<"\n"; system("pause"); return 0; }
//program to find the factorial value f any number using while loop #include<stdio.h> void main() { int i,n,fact=1; printf("Enter the number\n"); scanf("%d",&n); i=n; while (i>=1) { fact=fact*i; i--; } printf("The factorial value=%d",fact); } the above is a program for calculating tha factorial value of any number which is entered by the user
factorial number Var num= prompt("enter any number "); Var i=1; Var fact=1; for(i=1;i
Use this function: long factorial(int N){if (N == 0){return 1;}else{return N*factorial(N-1);}}
report zbharath. data:num type i value 5, fac type i value 0. perform fact using num changing fac. write:/ 'factorial of',num,'is',fac. form fact. using value(f-num) type i. changing f-fact type i. f-fact=1. while f-num ge 1. f-fact=f-fact*f-num. f-num=f-num-1. endwhile. endform.