the answer can be done by using perpendicular axis theorem that is using
Iz=Ix+Iy and the answer is ma*2/12
The simple scalar method of calculation is to integrate the square of the radius (r) across dm, where m is the mass. (Integral r2 dm is the equation, but we don't have an integral sign here.) Use the link to Wikipedia for the rest of the information and expansions on the "basic" equation.
Each side of the square would measure 2,828.43 feet making the perimeter of the square 11,313.72 feet. The diagonal of the square would be 4,000 feet.
A 40-acre square is 1,320 feet on each side.
The molecular shape is square pyramidal because it has five ligands and one lone pair and the bond angle are 90,<120. Also, it has no dipole moment and the electron group geometry is octahedral.
Simple Answer:If the Earth shrinks, the day gets shorter and the Earth rotates faster. But, that involves certain assumptions. See below.Angular Momentum:This is a question about angular momentum.If the change in size of the Earth is a result of an internal process and no external forces are involved, then total angular momentum is conserved. Angular momentum is the sum (integral) of all mass times velocity times the distance from the axis of rotation. That sum will stay the same as you redistribute mass with no external influences. If mass gets closer to the axis of rotation, then some mass has to go faster.The moment of inertia of a uniform sphere is I=2MR^2/5. Angular momentum is L=I omega. Omega is 2 pi/T and the period, T, is one day. So, L=2 pi I T. (The Earth is not uniform, but the result is the same.) If you keep M fixed and the density uniformly increases, then omega decreases. We can't get too precise without discussing more details, but the simple analysis suggests, T/R^2 is constant, so the period is proportional to square of the radius. Halve the radius and the day decreases to one fourth.
a^4/12
5ma^2/12
Mass moment of Inertia of the motor/Gearmotor is called GD2
It is the square root of ratio moment of inertia of the given axis to its mass.
A motor when running has inertia in the rotating parts, which is a reserve of kinetic energy. The kinetic energy is found as the moment of inertia times the square of the angular velocity.
I section has more moment of inertia than any other sections like square or rectangular section. More moment of inertia implies more resistance to bending and hence stiffer.
Most of the mass of a flywheel is concentrated at the rim so as to have a larger moment of inertia for the same mass. This is due to the fact that the moment of inertia varies as the square of the distance from the axis of rotation.
Most of the mass of a flywheel is concentrated at the rim so as to have large moment of inertia for the same mass.This is due to the fact that the moment of inertia varies as the square of the distance from the axis of rotation.
The diagonal of a square is not perpendicular to its side. The diagonal of a square will separate the square into two triangles. The diagonal goes from one corner to the opposite corner. Because it is a square, the diagonal and a side of the square will always form a 45-degree angle.
As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.
Moment of Inertia is defined as the product of mass and square of distance from its axis of rotation and it is denoted by I. I=mR2 Moment of Inertia depends upon mass from the axis of rotation of wheel rim e.g because the mass of big bicycle lie away from the axis of rotation of wheel rim.So M.O.I of big bicycle is Small than small Bicycle.
The diagonal of a 101 inch square is about 142.84 inches.