5ma^2/12
Because a ray that passes through the center of curvature falls perpendicular to the surface (along a normal to the surface), hence it is reflected along the same path.
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Because the center of curvature is defined to be in the direction of the normal. remember that a reflecting angle of light, relative to the normal, equals minus the angle of the beam that hit the mirror, relative to the normal. since the center of curviture is in the direction of the normal. A beam going through it would be with an angle of zero, and there for return with an angel of (minus) zero. In other words it comes back in the same direction.
Seems to me it has to be the line that passes through the mid-point of the line joining the charges, and perpendicular to it. It would be a line with slope = -1 / (slope of line joining the charges) and passing through the point that's (d/2) distant from both charges.
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the moment of inertia of a body about a given axis is equal to the sum of its moment of inertia about a parallel axis passing through its centre of mass and the product of its mass and square of perpendicular distance between two axis Iz=Ix+Iy
There is no name for it except "A line perpendicular to a line segment and passing through its midpoint".
Perpendicular to a line passing through the center of the Earth.
Perpendicular lines passing through a point are at right angles to each other.
the moment of inertia of a solid cylinder about an axis passing through its COM and parallel to its length is mr2/2 where r is the radius.
It does not have a specific name.
The slope of the perpendicular to the line passing through P1(3,6) and P2(5,1) is 2/5. Note: the slope of the original line is (change in y)/(change in x), yielding -5/2. The slope of the perpendicular is the negative reciprocal, 2/5
-9.8 m/s/s from the top, side=0
Points: (5, -1) and (2, -5) Slope: 4/3 Perpendicular slope: -3/4
y=-x
Infinite. The line is perpendicular to the ordinate.
Points: (3,-4) and (-1, -2) Midpoint: (1,-3) Slope: -1/2 Perpendicular slope: 2 Perpendicular bisector equation in slope intercept form: y = 2x-5