It has 7 electrons in its valance shell so it needs only 1 electron to form a octet; the Nobel gas configuration.
Fluorine has 7 valence electrons. 2 In the first electron shell, and 5 in the second electron shell.
A fluorine atom has 7 valance electrons. This can be identified by looking which group fluorine is located, which is group 7. However when the atoms get bigger this rule does not apply so easily.
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The electron configuration for an atom of fluorine is [He]2s2.2p5.
7 valence electrons
It has 7 electrons in its valance shell so it needs only 1 electron to form a octet; the Nobel gas configuration.
Fluorine has 7 valence electrons. 2 In the first electron shell, and 5 in the second electron shell.
7
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Chlorine has 7 valance electrons so the easiest way for it to fill it's valance shell and have an octet is to be an electron acceptor; an anion.
A fluorine atom has 7 valance electrons. This can be identified by looking which group fluorine is located, which is group 7. However when the atoms get bigger this rule does not apply so easily.
1
XeF4 Xe has 8 valance electrons. F has 7 valance electrons * 4 = 28 valance electrons 8 + 28 = 36 valance electron total. Now, there are 4 bonds between Xe and the 4 F's, so that is a total of 8 electrons shared. 36 - 8 = 28 valance electrons left over. That means that 6 each go around the fluorine atoms as three lone pair per atom and one electron for the exon atom, unless this is a charged molecule.
hundereds
The addition of an electron in Fluorine atom makes it fluoride ion so no of electrons are higher than protons , the extra electron produces repulsive force in outermost shell and electrons move away from nucleus and hence radius of electronic cloud is larger than fluorine atom.
The Halogen family (which consists of Fluorine, Chlorine, Bromine, Iodine and Astatine) have 7 valance electrons. I know that the atoms of these elements only need to GAIN 1 electron to fill their outtermost energy level.