If resistance is halved while voltage remains constant, the current will double.
If you double the voltage in a circuit, the power is quadrupled, assuming the resistance stays the same.
Using Ohms Law: V = I x R, where V (Voltage), I (Current), and R (Resistance). re-arranging: V/R = I Therefore if you double both the Voltage and the Resistance, the current remains unchanged.Current = Voltage / Resistance. If both resistance and voltage double the current remains the same.
It is halved. coz voltage=current * resistance
The physical equation governing voltage is V = IR, where V is voltage, I is current, and R is resistance. If V remains constant while R is increased, I or current must decrease. Increasing the resistance in a circuit is simply introducing a material that further resists or impedes the electron flow (current), thus current decreases.
In a passive circuit, the current will decrease. In an active industrial circuit, it will usually decrease. In a theoretic manner - it is an unknown.
If you double the voltage in a circuit, the power is quadrupled, assuming the resistance stays the same.
Using Ohms Law: V = I x R, where V (Voltage), I (Current), and R (Resistance). re-arranging: V/R = I Therefore if you double both the Voltage and the Resistance, the current remains unchanged.Current = Voltage / Resistance. If both resistance and voltage double the current remains the same.
It is halved. coz voltage=current * resistance
V = IR Where, V = voltage I = current R = resistance Thus if resistance is increased with constant voltage current will decrease
Inversely. As resistance increases, current dereases; given that the applied voltage is constant.
No it cant. Voltage = Current x Resistance. So at constant Voltage if the Resistance is increased, Current will reduce
Current will increase
If the ratio of voltage to current is constant, then the circuit is obeying Ohm's Law. If the ratio changes for variations in voltage, then the circuit does not obey Ohm's Law.
The physical equation governing voltage is V = IR, where V is voltage, I is current, and R is resistance. If V remains constant while R is increased, I or current must decrease. Increasing the resistance in a circuit is simply introducing a material that further resists or impedes the electron flow (current), thus current decreases.
As long as the voltage between the ends of the circuit remains constant, the current through the circuit is inversely proportional to the total effective resistance of the circuit.
by adding the the resistances in series the total resistance of the circuit increses and thus the crunt flowing in the circuit decrese. Ans 2 . the current in series circuit of constant resistance will always be the same . It will not effect the current .
Reducing the current to a circuit causes a higher resistance -- assuming constant Volts. Also, reducing the current to a circuit causes lower Volts -- assuming constant resistance.AnswerAltering the current has absolutely no effect on a circuit's resistance. Reducing the current will reduce line losses (I2R) and reduce the voltage drop along a conductor.