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For a thermodynamic system the COP is 5 and the heat supplied to the system is 1 KW?
Wiki User
∙ 8y ago
This looks like the beginning of a question - but it never gets around to the question. Without a question being asked, it's pretty hard to provide an answer.
For the benefit of anyone who stumbles upon this non-question, I'm guessing that they might have been looking for the work required to supply 1 KW of heat to the reservoir of a system where the COP is 5.
COP is the acronym for "coefficient of performance". It is defined as COP = Q/W where Q is the heat supplied to or removed from the reservoir. If Q is 1kw and the COP is 5, then it would take W = Q/COP = 1 kW/5 = 0.2 kW of work to supply that heat.
Wiki User
∙ 8y ago
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What does heat pump COP stand for?
Coefficiency of performance.
Why coefficient of performance of absorption cycle is less than compression cycle?
In case of vapour compression cycle (VCC) the COP is given by (desired effect / work input). in the other words it can be defines as what we want and what we are paying for that... so in VCC the paying amount is very less as due to low temperature difference that why its value is more than 1. but in case of vapour absorption system the COP is given by (heat taken by evaporator/ heat given to generator). the heat input taken by evaporator is less as compared to heat given to generator.. that why its COP is less than 1......
When carnot cycle is reversed derive relation for coefficiency of performance for heat pump and refrigerator?
in refrigeration CoP =Qo/w= Todelta S/(Tk-To)delta S= To/Tk-ToEc = 1/(Tk/To)-1in heat pump CoP = Qk/W= Tkdelta S/(Tk-To) delta S= Tk/Tk-ToEh = 1/1-(To/Tk)
What will be the COP of a domestic refrigerator available in the market?
1
What is the cop of vapour compression cycle?
3. Vapour Compression Refrigeration CycleVapor-compression refrigeration is one of the many refrigeration cycles available for use. It has been and is the most widely used method for air-conditioning of large public buildings, offices, private residences, hotels, hospitals, theaters, restaurants and automobiles. It is also used in domestic and commercial refrigerators, large-scale warehouses for chilled or frozen storage of foods and meats, refrigerated trucks and railroad cars, and a host of other commercial and industrial services. Oil refineries, petrochemical and chemical processing plants, and natural gas processing plants are among the many types of industrial plants that often utilize large vapor-compression refrigeration systems. Refrigeration may be defined as lowering the temperature of an enclosed space by removing heat from that space and transferring it elsewhere. A device that performs this function may also be called a heat pump.The vapor-compression uses a circulating liquid refrigerant as the medium which absorbs and removes heat from the space to be cooled and subsequently rejects that heat elsewhere. Figure 1 depicts a typical, single-stage vapor-compression system. All such systems have four components: a compressor, a condenser, a Thermal expansion valve (also called a throttle valve), and an evaporator. Circulating refrigerant enters the compressor in the thermodynamic state known as a saturated vapor and is compressed to a higher pressure, resulting in a higher temperature as well. The hot, compressed vapor is then in the thermodynamic state known as a superheated vapor and it is at a temperature and pressure at which it can be condensed with typically available cooling water or cooling air. That hot vapor is routed through a condenser where it is cooled and condensed into a liquid by flowing through a coil or tubes with cool water or cool air flowing across the coil or tubes. This is where the circulating refrigerant rejects heat from the system and the rejected heat is carried away by either the water or the air (whichever may be the case).The condensed liquid refrigerant, in the thermodynamic state known as a saturated liquid, is next routed through an expansion valve where it undergoes an abrupt reduction in pressure. That pressure reduction results in the adiabatic flash evaporation of a part of the liquid refrigerant. The auto-refrigeration effect of the adiabatic flash evaporation lowers the temperature of the liquid and vapor refrigerant mixture to where it is colder than the temperature of the enclosed space to be refrigerated.The cold mixture is then routed through the coil or tubes in the evaporator. A fan circulates the warm air in the enclosed space across the coil or tubes carrying the cold refrigerant liquid and vapor mixture. That warm air evaporates the liquid part of the cold refrigerant mixture. At the same time, the circulating air is cooled and thus lowers the temperature of the enclosed space to the desired temperature. The evaporator is where the circulating refrigerant absorbs and removes heat which is subsequently rejected in the condenser and transferred elsewhere by the water or air used in the condenser.To complete the refrigeration cycle, the refrigerant vapor from the evaporator is again a saturated vapor and is routed back into the compressor.Refrigeration ProcessProcess Description1-2s: A reversible, adiabatic (isentropic) compression of the refrigerant.The saturated vapour at state 1 is superheated to state 2.⇒ wc = h2s− h12s-3: An internally, reversible, constant pressure heat rejectionin which the working substance is desuperheated and then condensedto a saturated liquid at 3. During his process, the working substancerejects most of its energy to the condenser cooling water.⇒ qH = h2s− h33-4 An irreversible throttling process in which the temperature andpressure decrease at constant enthalpy.⇒ h3 = h44-1 An internally, reversible, constant pressure heat interactionin which the working fluid is evaporated to a saturated vapourat state point 1. The latent enthalpy necessary for evaporationis supplied by the refrigerated space surrounding the evaporator.The amount of heat transferred to the working fluid in the evaporatoris called the refrigeration load.⇒ qL = h1− h4
What is the cofficient of performance in the refrigeration system?
Coefficient of performance, or COP, is defined differently for heating and cooling applications. For heating: COP=(heat supplied + work)/work For cooling: COP=(heat removed)/work Work in this case refers to the compressor and other motors.
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What does COP stand for from a thermodynamic stand point?
COP in thermodynamics usually refers to the Coefficient Of Performance(sometimes CP) andis the ratio of the heating or cooling provided over the electrical energy consumed.COPheating = |QH|/W = (|QC| + W)/WCOPcooling = |QC|/WwhereQC is the heat removed from the cold reservoirQH is the heat supplied by the hot reservoirThe COP provides a measure of performance for heat pumps that is analogous to thermal efficiency for power cycles. In the case of a refrigerator, the cold reservoir is the air in the room around the refrigerator and the hot reservoir is the interior of the refrigerator - counterintuitive as that may sound. In the case of the refrigerator, the refrigerant is compressed such that it is hotter than the room, thus making it a source of heat. Part of the energy comes from the interior of the refrigerator (QC) and the rest from the work done by the compressor. When a heat pump is used to warm a building, the outside air is the hot reservoir - even though it may be colder than inside the building. Once again, the fluid used in the heat pump is compressed so that it can dump heat into the building and then when expanded outside, it is cold enough to absorb energy from the outside air.
Does domestic refrigerator have more cop than air conditioner?
COP of any refrigerating system mainly depends on the performance of the compressors used and the heat load at the evaporator. A similar or almost equal COP can be achieved from any system by varying its working parameters like load, kind of refrigerant used and the system working pressure. For more details contact maheshkannajpr@gmail.com
What does heat pump COP stand for?
Coefficiency of performance.
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Why coefficient of performance of absorption cycle is less than compression cycle?
In case of vapour compression cycle (VCC) the COP is given by (desired effect / work input). in the other words it can be defines as what we want and what we are paying for that... so in VCC the paying amount is very less as due to low temperature difference that why its value is more than 1. but in case of vapour absorption system the COP is given by (heat taken by evaporator/ heat given to generator). the heat input taken by evaporator is less as compared to heat given to generator.. that why its COP is less than 1......
A heat pump has a cop rating of 2.5 to 1 if 200 watts of electricity are used to run the heat pump how many equivalent watts are produced?
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